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Luba_88 [7]
3 years ago
7

How do you find the net force of 225 N

Physics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

2.65

Explanation:

Its simple just find the newtons

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What is the weight of a person with a massa of 80kg
Archy [21]
784 Newtons or 176.37 lbs
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A sprinter with a mass of 80 kg accelerates from 0 m/s to 9 m/s in 3 s. What is the runner's acceleration?
sertanlavr [38]
Acceleration = (change in speed) / (time for the change) = 9/3 = <em>3 m/s²</em> .

His mass makes no difference.
5 0
3 years ago
Which type of energy releases greenhouse gases when used to make electricity?
Elan Coil [88]
A) Geothermal
B) Hydroelectric
C)Biomass
D) Wind

I assume this is the four options you had, correct?

i think that biomass is the only one that would release the greenhouse gases. I once heard, it may not be true, that biomass has more co2 released than coal.
4 0
3 years ago
Read 2 more answers
Is mass is 88.2 and height of distance is 25m, how do you find speed?
Natasha_Volkova [10]

Answer:

The velocity will be v = 22.1[m/s]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy is converted to kinetic energy. For this problem we will take the point with maximum potential energy when the body is 25 [m] high. By the time the height is zero, the potential energy will have been transformed into kinetic energy, and we can find the velocity of the body.

Ep = m*g*h\\where:\\m = mass = 88.2[kg]\\h = elevation = 25[m]\\g = gravity = 9.81 [m/s^2]\\Ep = 88.2*25*9.81 = 21631.05[J]\\

Now we know that the energy will be transformed.

Ek=Ep\\Ek=0.5*m*v^{2} \\where:\\v=velocity [m/s]\\v=\sqrt{\frac{Ek}{0.5*m} } \\v=\sqrt{\frac{21631.05}{0.5*88.2} } \\v=22.14[m/s]

4 0
3 years ago
A long thin rod of mass M and length L is situated along the y axis with one end at the origin. A small spherical mass m1 is pla
Yuri [45]

Answer:

= - 5.65\times 10^{-2} J

Explanation:

Given data:

L =2.00 *10^4 m

d = 18*10^4 m

M = 18  *10^6 kg

m_1 = 8*10^6 kg

Gravitational energy is given as

U =- G \frac{m_1 m_2}{r}

mass per unit length is given as

\sigma = \frac{M}{L} = \frac{18 \times 10^6}{2\times 10^4 m} = 900 kg/m

calculating potential energy

dU ==-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *dm}{r}

=-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *\sigma dr}{r}

=-G*m_1*\sigma\int_{16\times 10^4}^{18\times 10^4} \frac{dr}{r}

=-G*m_1*\sigma \left | ln r \right |_{16\times 10^4}^{18\times 10^4}

=-G*m_1*\sigma ln(1.125)

=-6.673 \times 10^{-11}*8*10^6*900*ln(1.125)

= - 5.65\times 10^{-2} J

5 0
3 years ago
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