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Naddik [55]
3 years ago
14

2C6H10 + 17O2 = 12CO2 + 10H2O

Chemistry
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

n O2 = 2.125 mol

Explanation:

balanced reaction:

  • 2C6H10 + 17O2 → 12CO2 + 10H2O

∴ n CO2 = 1.5 mol

⇒ n O2 = (1.5 mol CO2)*(17 mol O2/12 mol CO2)

⇒ n O2 = 2.125 mol

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Determine the enthalpy change for the decomposition of calcium carbonate. CaCO₃(s) --> CaO(s) + CO₂(g) given the thermochemic
Hunter-Best [27]

Answer: c. 179 kJ/mol

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Given:

Ca(OH)_2(s)\rightarrow CaO(s)+H_2O (l)   \Delta H_1= 65.2 kJ/mol     (1)

Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)    \Delta H_2= -113.8 kJ/mol   (2)

C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_3= -393.5 kJ/mol   (3)

2Ca(s)+O_2(g)\rightarrow 2CaO(s) \Delta H_4=-1270.2 kJ/mol    (4)

On subtracting eq (1) from eq (2) we have:

Ca(OH)_2(s)\rightarrow CaO(s)+H_2O(l) - Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

\Delta H=-113.8-(65.2)kJ/mol=-179kJ/mol

Hence the enthalpy change for the raection is 179.0 kJ/mol.

6 0
3 years ago
All of the following are signs of chemical change except
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What is the name of the compound composed of iron and carbonate? [hint: iron has a +3 charge in this compound]?
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4 years ago
A specific combination of bonded atoms which always react in the same way is known as
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4 0
4 years ago
Which of the following numerical expressions gives the number of particles in 2.0 g of Ne?
mojhsa [17]

Answer:

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

Explanation:

Step 1: Data give

Mass of Ne = 2.0 grams

Molar mass of neon = 20.18 g/mol

Number of Avogadro = 6.0 *10^23 /mol

Step 2: Calculate number of moles of neon

Moles Ne = Mass of ne / Molar mass of ne

Moles Ne = 2.0 / 20.18 g/mol

Moles Ne = 0.099 moles

Step 3: Calculate nulber of particles

Number of particles = 6.022*10^23 / mol * 0.099 moles = 5.96 *10^22

Number of particles = 6.022*10^23 * (2.0g/ 20.18g/mol)

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

7 0
3 years ago
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