The resulting pressure of the gas after decreasing the initial volume from 2 L to 1 L is 3 atm.
<h3>What is
Boyle's Law?</h3>
According to the Boyle's Law at constant temperature, pressure of the gas is inversely proportional to the volume of that gas.
For the given question we use the below equation is:
P₁V₁ = P₂V₂, where
P₁ = initial pressure of gas = 1.5 atm
V₁ = initial volume of gas = 2 L
P₂ = final pressure of gas = ?
V₂ = final volume of gas = 1 L
On putting all these values on the above equation, we get
P₂ = (1.5atm)(2L) / (1L) = 3 atm
Hence required pressure of the gas is 3 atm.
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The answer fam is......... False
1) You need to get volume of both temperatures by using first attached formula V= Mass/Density

2) Using the second formula you get the height of 0 degree

(radius in cm is

3) Then with h1 you can easily get the height of 25 degrees
Subtract 943.5 cm - 939.2 cm, and obtain a rise in mercury height of 4.3 cm