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Bess [88]
4 years ago
5

A chemist dissolves 660.mg of pure hydroiodic acid in enough water to make up 300.mL of solution. Calculate the pH of the soluti

on.
Chemistry
1 answer:
dlinn [17]4 years ago
5 0

Answer:

0.23

Explanation:

Mass= 600mg, Volume =300ml

To get the number of mole of HCl

n = mass/molar mass = 600/36.5 = 18.02 mole

Now to he the concentration of HCl

C= n / v

= 18.02/300

= 0.603mol/ml

But pH = - log [hydrogen ion]

Therefore pH = - log 0.603

=0.23

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The half-life of nitrogen-13 is 10.0 minutes. if you begin with 53.3 mg of this isotope, what mass remains after 25.9 minutes ha
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Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 53.3 mg

m (final mass after time T) = ? (in mg)

x (number of periods elapsed) = ?

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Let's find the number of periods elapsed (x), let us see:

T = x*P

25.9 = x*10.0

25.9 = 10.0\:x

10.0\:x = 25.9

x = \dfrac{25.9}{10.0}

\boxed{x = 2.59}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{53.3}{2^{2.59}}

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\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

3 0
3 years ago
how much energy would it take to heat a section of the copper tubing that weights about 660.0 gram, from 12.93 degree Celsius to
expeople1 [14]

Answer:

                      Q  =  2647 J

Explanation:

                    Specific heat capacity is the amount of energy required by one Kg of a substance to raise its temperature by 1 °C.

In thermodynamics the equation used is as follow,

                                                 Q  =  m Cp ΔT

Where;

           Q  =  Heat  =  ?

           m  =  mass  =  660 g

           Cp  =  Specific Heat Capacity  =  0.3850 J.g⁻¹.°C⁻¹

           ΔT  =  Change in Temperature  =  23.35 °C - 12.93 °C  =  10.42 °C

Putting values in eq. 1,

                            Q  =  660 g × 0.3850 J.g⁻¹.°C⁻¹ ×  10.42 °C

                            Q  =  2647 J

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4 years ago
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