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marishachu [46]
3 years ago
6

What happened when a drop of the sodium carbonate solution was mixed with the magnesium sulfate?

Chemistry
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

The formation of magnesium carbonate in the form of a precipitate and sodium sulfate as a byproduct takes place.

Explanation:

When a drop of sodium carbonate is mixed with the magnesium sulfate, the formation of MgCO3, magnesium carbonate as a precipitate, and Na2SO4, sodium sulfate as a byproduct takes place. One can separate magnesium carbonate from the sodium sulfate by using the process of filtration. The chemical reaction that takes place in the process is:  

MgSO4 (aq) + Na2SO4 (aq) ⇒ MgCO3 (s) + Na2SO4 (aq)

A separation process in which the formation of solid takes place in a solution after undergoing a chemical reaction is termed as precipitation. The precipitate is the name given to the solid substance that gets produced in the reaction. The precipitate formed can be withdrawn from the solution with the help of a physical separation procedure like filtration.  

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Answer:

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3 years ago
Solution with a ph of 3 has how many times more h+ ions than one with a ph of 4? 5?
Lerok [7]
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How would you properly measure the mass of a liquid
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4 0
3 years ago
The reaction of HCl with NaOH is represented by the equation HCl( aq) + NaOH( aq) ® NaCl( aq) + H 2O( l) What volume of 0.631 M
Darina [25.2K]

8.04 mL.

<h3>Explanation</h3>

How many moles of NaOH?

Note the unit:

V = 15.8 \; \textbf{mL} = \dfrac{15.8}{1000}\;\textbf{L} = 0.0158 \; \text{L}.

n = c\cdot V = 0.0158 \times0.321 = 0.00507\;\text{mol}.

How many moles of HCl?

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n(\text{HCl}) = n(\text{NaOH}) = 0.00507\;\text{mol}.

How many mL of HCl?

V = \dfrac{n}{c} =\dfrac{0.00507}{0.631} = 0.00804\;\text{L} = 0.00804\times 1000 \;\textbf{mL} = 8.04\;\text{mL}.

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3 years ago
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