For this case we must simplify the following expression:
We apply distributive property on the left side of the equation:
We subtract 3n from both sides of the equation:
We subtract 6 from both sides of the equation:
We divide between 45 on both sides of the equation:
Answer:
Answer:
24
Step-by-step explanation:
In the first classroom, there are 4 possibilities of teachers to be assigned.
In the second classroom, 1 teacher has already been assigned, so there are 3 possibilities.
In the third classroom, 2 teachers have already been assigned, so there are only 2 possibilities.
Finally, there is only 1 possible teacher for the fourth classroom, since 3 teachers have already been assigned to other classrooms.
We can find the total number of possibilities using the product rule.
N = 4 × 3 × 2 × 1 = 24
Answer:
x^2-4x+4-(x^2+6x+9)
Step-by-step explanation:
=x^2-4x+4-x^2-6x-9
=-10x - 5
Answer:
Variance = 1,227.27
Standard deviation = 35.03
Step-by-step explanation:
To calculate these, we use the following formulas:
Mean = (sum of the values) / n
Variance = ((Σ(x - mean)^2) / (n - 1)
Standard deviation = Variance^0.5
Where;
n = number of values = 20
x = each value
Therefore, we have:
Sum of the values = 29 + 32 + 36 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150 = 1,674
Mean = 1,674 / 20 = 83.70
Variance = ((29-83.70)^2 + (32-83.70)^2 + (36-83.70)^2 + (40-83.70)^2 + (58-83.70)^2 + (67-83.70)^2 + (68-83.70)^2 + (69-83.70)^2 + (76-83.70)^2 + (86-83.70)^2 + (87-83.70)^2 + (95-83.70)^2 + (96-83.70)^2 + (96-83.70)^2 + (99-83.70)^2 + (106-83.70)^2 + (112-83.70)^2 + (127-83.70)^2 + (145-83.70)^2 + (150-83.70)^2) / (20 - 1) = 23,318.20 / 19 = 1,227.27
Standard deviation = 1,227.27^0.5 = 35.03
Answer:
B. 66
Step-by-step explanation:
Substitute x = 3
Multiply in the parentheses
(6 + 192) Add
(198) Multiply
66
