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3 years ago

How do driver of cars use galvanometer

1 answer:

6 0

<span>Electricians use them and drivers of cars use them to know when to stop for fuel.. If a wire with a current moved upward in a magnetic field, how would it move when the direction of ... What energy transformation occurs in a galvanometer?</span><span>
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What is the physical properties of radon

ryzh [129]

Answer:

<h2 /><h2>1) Radon is colorless at standard temperature and pressure and it is the most dense gas known. At temperature below it's freezing point is has a brilliant yellow phosphorescence. It is chemically unreactive, it is highly radioactive and has a short half life.</h2>

<h2>2) 7.5 times heavier than air and more than 100 times heavier than hydrogen. The gas liquefies at −61.8 °C (−79.2 °F) and freezes at −71 °C (−96 °F). On further cooling, solid radon glows with a soft yellow light that becomes orange-red at the temperature of liquid air (−195 °C [−319 °F]).</h2>

Explanation:

<h2>I think this much is enough , as more information </h2><h2>is given in other answer if more is needed just </h2><h2>comment me I will answer you there only.</h2>

5 0

3 years ago

An electron is released from rest in a uniform electric field of 418 N/C near a particle detector. The electron arrives at the d

Oksanka [162]

Answer:

a) 7.35 x 10¹³ m/s²

b) 5.03 x 10⁻⁸ sec

c) 9.3 cm

d) 6.23 x 10⁻¹⁸ J

Explanation:

E = magnitude of electric field = 418 N/C

q = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

m = mass of the electron = 9.1 x 10⁻³¹ kg

acceleration of the electron is given as

$a = \frac{qE}{m}$

$a = \frac{(1.6\times 10^{-19})(418)}{(9.1\times 10^{-31})}$

a = 7.35 x 10¹³ m/s²

v = final velocity of the electron = 3.70 x 10⁶ m/s

v₀ = initial velocity of the electron = 0 m/s

t = time taken

Using the equation

v = v₀ + at

3.70 x 10⁶ = 0 + (7.35 x 10¹³) t

t = 5.03 x 10⁻⁸ sec

d = distance traveled by the electron

using the equation

d = v₀ t + (0.5) at²

d = (0) (5.03 x 10⁻⁸) + (0.5) (7.35 x 10¹³) (5.03 x 10⁻⁸)²

d = 0.093 m

d = 9.3 cm

Kinetic energy of the electron is given as

KE = (0.5) m v²

KE = (0.5) (9.1 x 10⁻³¹) (3.70 x 10⁶)²

KE = 6.23 x 10⁻¹⁸ J

4 0

4 years ago

Identify at least one example each of absorption, transmission, reflection, and refraction of waves in this photograph.

Ronch [10]

Answer:

hi,human absorb 0oxygen =aborption ,reflection =the light that entered in the water,refraction =the light that pass outside the water

Explanation:

8 0

3 years ago

Read 2 more answers

What is the quality of the sound of a fire truck’s siren when it moves toward a stationary hearer?

Doss [256]

<span>What is the quality of the sound of a fire truck’s siren when it moves toward a stationary hearer?
Its High Pitched

</span>

What is the quality of the sound of a fire truck’s siren when it moves away from a stationary hearer?

Its Low Pitched

6 0

3 years ago

Read 2 more answers

A 75.0-kg person is riding in a car moving at 20.0 m/s when the car runs into a bridge abutment. (a) calculate the average force

iragen [17]

(a) $-1.5\cdot 10^6 N$

First of all, we need to calculate the acceleration of the person, by using the following SUVAT equation:

$v^2 -u ^2 = 2ad$

where

v = 0 is the final velocity

u = 20.0 m/s is the initial velocity

a is the acceleration

d = 1.00 cm = 0.01 m is the displacement of the person

Solving for a,

$a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.01)}=-20000 m/s^2$

And the average force on the person is given by

$F=ma$

with m = 75.0 kg being the mass of the person. Substituting,

$F=(75)(-20000)=-1.5\cdot 10^6 N$

where the negative sign means the force is opposite to the direction of motion of the person.

b) $-1.0\cdot 10^5 N$

In this case,

v = 0 is the final velocity

u = 20.0 m/s is the initial velocity

a is the acceleration

d = 15.00 cm = 0.15 m is the displacement of the person with the air bag

So the acceleration is

$a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.15)}=-1333 m/s^2$

So the average force on the person is

$F=ma=(75)(-1333)=-1.0\cdot 10^5 N$

7 0

4 years ago