<u>Answer:</u>
Cannonball will be in flight before it hits the ground for 2.02 seconds
<u>Explanation:</u>
Initial height from ground = 20 meter.
We have equation of motion , 
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 
, we need to calculate time when s = 20 meter.
Substituting
So it will take 2.02 seconds to reach ground.
Vehicle Kinematics: a
vehicle sliding sideways into a gravel pit, a vehicle
driving down a bank, a vehicle driving up a ramp and
a vehicle sliding laterally against a curb. "sliding
laterally against a curb" and "sliding sideways into a
gravel pit".
First you do 2.5 n-m / 2 kg-m2
This equals 1.25 rad/s^2
Then multiply rad/s^2 by 10 because of the amount of seconds
This equals 12.5 rad/s^2
Then do this following equation : (1/2)Iwf^2
Do (0.5) 12.5 * 12.5 * 2
This equals 156.25 J (meaning that the answer is C: 156 J)
Answer:
you didn't post any triangles. Thus, the question could not be answered.
I believe it’s false, I think I had this before
