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Bingel [31]
2 years ago
10

49. In what direction does the force of friction act?

Physics
1 answer:
liubo4ka [24]2 years ago
6 0
Frictional force offers the resistance to the applied force opposing its motion. Thus, it always acts in the direction opposite to that of the object in motion. If force is applied to the left, then friction acts in the right.
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Two converging lenses are separated by 27.0 cm. The focal length of each lens is 8.90 cm. An object is placed 33.0 cm to the lef
Ymorist [56]

Answer:

1/i + 1/o = 1/f     thin lens equation

i = 33 * 8.9 / (33 - 8.9) = 12.2 cm  to right of first lens

27 - 12.2 = 14.8 cm to left of second lens

i = 14.8 * 8.9 / (14.8 - 8.9) = 22,3 cm to right of second lens

7 0
2 years ago
Please help if you have the time
Alex777 [14]

We know, length of segment wave is half the wavelength .

Let, wavelength of wave is \lambda.

So, length of segment will be \dfrac{\lambda}{2} .

Now, it is given that the string vibrates in four segments.

So,

L = 4\times \dfrac{\lambda}{2}\\\\L = 2\lambda\\\\\lambda = 1\ m

Speed can be given by :

speed = wavelength \times frequency\\\\speed = 1\times 120\  m/s\\\\speed = 120\ m/s

Therefore, the wave speed in the string is 120 m/s.

6 0
2 years ago
According to Newton's first law, an object in motion will stay in motion unless:
Nadusha1986 [10]

Answer: unless it's acted upon by an external force

Explanation: Newton first law of motion State that an object will continue in it state of rest or in motion, unless it is been acted upon by an external force

8 0
3 years ago
One of the difficulties in studying mechanics is that many common words are used with highly specific technical meanings,among t
Allisa [31]

Mnanan anaw anwkkww wjakana akkqna akaoaman akamakq

8 0
2 years ago
A physics professor is pushed up a ramp inclined upward at an angle 33.0° above the horizontal as he sits in his desk chair tha
Andru [333]

Answer:

2.51 m/s

Explanation:

Parameters given:

Angle, A = 33°

Mass, m = 90kg

Inclined distance, D = 2m

Force, F = 600N

Initial speed, u = 2.3m/s

From the relationship between work and kinetic energy, we know that:

Work done = change in kinetic energy

W = 0.5m(v² - u²)

We also know that work done is tẹ product of force and distance, hence, net work done will be the sum of the total work done by the force from the students and gravity.

Hence,

W = F*D*cosA - w*D*sinA

w = m*9.8 = weight

=> W = 600*2*cos33 - 90*9.8*2*sin33

W = 45.7J

=> 45.7 = 0.5*m*(v² - u²)

45.7 = 0.5*90*(v² - 2.3²)

45.7 = 45(v² - 5.29)

=> v² - 5.29 = 1.016

v² = 6.306

v = 2.51 m/s

The final velocity is 2.51 m/s

7 0
3 years ago
Read 2 more answers
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