Yes, the answer is in fact C. All of the above.
Variable stars are stars that change in brightness. The change could be due to the physical change in the star or it could also be caused when another star crosses another, or in other words eclipse.
Answer:
-22.2 m/s²
Explanation:
The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:
(1) 
For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:
(2) 
Solving for time t:

(3) 
The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:
(4) 
Solving equation 4 for acceleration of rocket B:
(5) 
Explanation:
If a positive test charge is placed in an electric field, it will exert the force in the test charge in the direction of electric field vector. We know that the direction of electric field is given by electric field lines. The field lines for a positive charge is outwards. The electric force acting on the charge is given by :
F = q E
Hence, this is the required solution.
Mass is the physical quantity
Energy is released in the reaction
Explanation:
In a given where the energy of the products is greater than that of the reactants, we can infer that energy is released in the reaction.
This indicates that the reaction is an exothermic or exergonic reaction.
These reaction types are accompanied by release of energy.
- In an exothermic change energy is released to the surroundings.
- The surrounding becomes hotter at the end of the change.
- This applies in exergonic reaction which leaves a reaction having more energy than it originally started with.
Learn more:
Exothermic process brainly.com/question/10567109
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