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Vinvika [58]
3 years ago
9

A solution is prepared by dissolving 6.00 g of an unknown nonelectrolyte in enough water to make 1.00 l of solution. the osmotic

pressure of this solution is 0.750 atm at 25.0^\circ c 25.0 ∘
c. what is the molecular weight (g/mol) of the unknown solute?
Chemistry
1 answer:
vovangra [49]3 years ago
7 0

Osmotic pressure can be calculated using the following equation:  

\prod =C\times R\times T

Here,

C representated concentration

R represented gas constant

T represented temperature

\prod  representated osmotic pressure

R=0.0821 atm L mol ⁻¹

T = 25 + 273 = 298 K

C=\frac{Given mass of the substance}{Molar mass of the substance\times Volume}  

Given mass of the substance= 6.00 g

Volume= 1 L

\prod =0.75 atm

Putting all the values in the equation:

0.750 =\frac{6}{Molar mass of the substance\times 1}\times 0.0821\times 298

Molar mass of the substance= 195 g mol⁻¹.

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