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4 years ago

WHICH OF THE FOLLOWING STATEMENTS CANNOT BE DETERMINED FROM THE DIAGRAM

Mathematics

1 answer:

Gelneren [198K]4 years ago

8 0

Answer:

Option (B).

Step-by-step explanation:

Option (A).

A, F and B are lying on a line on the plane M.

True.

Option (B).

CD lies on the plane M, but its not clear that angle between the plane M and P is 90°.

False.

Option (C).

A, B and C are coplanar.

Since, these three points lie on the plane M, they are coplanar.

True.

Option (D).

Plane M intersects plane P in FH.

Since, line of intersection of the two planes M and P will be FH.

True.

Therefore, Option (B) will be the correct option.

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Please help me fast:

Fiesta28 [93]

Answer:

45 − x % ∗ 45 = 38.25

− 45 x /100 = 38.25 − 45

− 45 x /100 = − 6.75

x = 6.75 ∗ 100 /45

= 15

8 0

4 years ago

Read 2 more answers

A triangle has side length of 10 inches, 24 inches, and 26 inches. Is the triangle a right triangle?

zaharov [31]

Yes, 10 squared+ 24 squared+ 26 squared

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3 years ago

PLS PLS PLS PLS HELP ASAP!! WILL MARK BRAINLIEST!

grandymaker [24]

Answer:

1. D

2. y = 15.50x + 450

Step-by-step explanation:

1. Since it is a function, the missing pair can't repeat input values with different output, therefore only option D is unique so is the correct choice.

2. x > (y - 450)/ 15.50

i) Rita gets paid $450 per week.

ii) She gets $15.50 for every new membership she sells.

iii) let y represent the total pay per week.

iv) let x represent the number of new memberships sold.

v) the equation representing total pay is y = 15.50x + 450.

vii) therefore the equation that represents a higher rate of membership sold is given by x > (y - 450)/ 15.50

8 0

3 years ago

Six stand-up comics, A, B, C, D, E, and F, are to perform on a single evening at a comedy club. The order of performance is

kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

$P(F=4th)=1/6$

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

$P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36$

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

$P(F, D, B, A, C, E)=1/720$

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

$P(C=6th\,or\, E=6th)=2/6=1/3$

8 0

4 years ago

H=2.9L+78.1<br> About how tall would the male have been if the length of the humerus measured 39 cm?

dalvyx [7]

Answer:H=191.2

Step-by-step explanation:

H=2.9(39)+78.1

H=113.1+78.1

H=191.2 cm

3 0

4 years ago