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3 years ago

7

The force between two charges is 1000 N. One has a charge of 2.0 x 10-5 C and one has a charge of 5.0 x 10-6 C. What is the dist

ance between the charges?

1 answer:

zalisa [80]3 years ago

6 0

Answer:

F= kq1q2÷r^2 r=√9x10^9 x 2.0 x 10^-5 x 5.0x 10^-6 ÷ 1000 ) the ansewer√300

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PLEAASE HELP KE WITH THESE THREE YOULL GET POINTS

lozanna [386]

Answer:

0.0121
19.8387
2.2632

Explanation:

1.

$\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{0.01223}{1.01}\:\\\mathrm{is}\:0.0121$

2.

$\frac{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&\space\space&\space\space&4&9&10\\ \space\space&\textbf{1}&9&.&8&\linethrough{5}&\linethrough{10}&\linethrough{0}\\ -&\textbf{0}&0&.&0&1&1&3\end{matrix}}{\begin{matrix}\space\space&\textbf{1}&9&.&8&3&8&7\end{matrix}}\\\\=19.8387$

3.

$0.1886\times 12\\\\Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer\\1886\times\:12=22632\\\\0.1886\mathrm{\:has\:}4\mathrm{\:decimal\:places}\\12\mathrm{\:has\:}0\mathrm{\:decimal\:places}\\\\\mathrm{Therefore,\:the\:answer\:has\:}4\mathrm{\:decimal\:places}\\\\=2.2632$

3 0

3 years ago

Whats the answer???????????????????????

murzikaleks [220]

The answer is 30 ... same as the Atomic number.

4 0

3 years ago

A ray in plastic has a critical angle of 44.4 deg when trying to enter air. What is the index of refraction for the plastic?

Elena-2011 [213]

Answer: 1.43

Explanation:

Given that:

C (critical angle) = 44.4°

n (refractive index of plastic) = ?

Apply the formula n = 1/sineC, the index of refraction for the plastic can be obtained by:

n = 1/sineC

n = 1/sine 44.4°

n = (1/0.6996)

n = 1.43

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8 0

4 years ago

Hunter aims directly at a target (on the same level) 75.0 m away. (a) If the bullet leaves the gun at a speed of 180 m/sby how m

tankabanditka [31]

Answer:

Part a)

$\delta y = 0.85 m$

Part b)

$\theta = 0.65 degree$

Explanation:

Part a)

As we know that the target is at distance 75 m from the hunter position

so here we will have

$x = v_x t$

here we know that

$v_x = 180 m/s$

so we have

$75.0 = 180 (t)$

$t = 0.42 s$

now in the same time bullet will go vertically downwards by distance

$\delta y = \frac{1}{2}gt^2$

$\delta y = \frac{1}{2}(9.81)(0.42^2)$

$\delta y = 0.85 m$

Part b)

In order to hit the target at same level we need to shot at such angle that the range will be 75 m

so here we have

$R = \frac{v^2 sin(2\theta)}{g}$

$75 = \frac{180^2 sin(2\theta)}{9.81}$

$\theta = 0.65 degree$

4 0

4 years ago

488 nm light passes through a single

swat32

Answer:

5.00

Explanation:

a sinθ=mλ

You are missing (a) so you move sinθ to the other side than solve from there.

5 0

3 years ago