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Mars2501 [29]
3 years ago
14

Can someone help me please

Chemistry
1 answer:
kap26 [50]3 years ago
4 0
(3 x 10^10 Hg) x (1 mole Hg/6.022 x 10^23 Hg) x (200.59g / 1 mole Hg) =
99.928 x 10^-13
10^-9 g Hg x (1 mole Hg / 200.59 g Hg) x (6.022 x 10^23 Hg / 1 mole Hg) =
0.031 x 10^14 Hg = 3.1 x 10^12 Hg
I.) 10^-11 g Hg
II.) 3.1 x 10^12 Hg

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Two samples of a compound containing elements a and b are decomposed. the first sample produces 15 g of a and 35 g of
Alborosie

According to law of definite proportion, for a compound, elements always combine in fixed ratio by mass.

The formula of compound remains the same, let it be a_{x}b_{y} where, a and b are two different elements.

Since, the ratio of mass remains the same , calculate the ratio of masses of element a and b in both cases

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