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3 years ago

? + ? = zink chloride + water

Chemistry

1 answer:

Elodia [21]3 years ago

8 0

Answer:

Zinc, hydrochloric acid

Explanation:

A metal plus an acid equals a salt plus water

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Round off or add zeros to the following calculated answers to give a final answer with three significant figures

sesenic [268]

In this case, 58.703 has five significant figures because the 3 at the end is significant and therefore makes the 0 significant as well. Since there are 5 significant figures, we need to round off the 7 to get 58.7, which has three significant figures.

Hope this helps.

8 0

3 years ago

How many molecules of o2 are produced from 82g of h2o? 2na2o2 +2h2o= o2 +4naoh

vovangra [49]

Answer:
857.2947

Explanation:

You start with what you’re given 82g of H20 and multiply by 1 mole and the actual grams of h20 which is 18.0 then you do the mole. 1 mol of O2 and 2 mol of H2O times 6.02 x 10^23

6 0

2 years ago

To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o

Romashka-Z-Leto [24]

Answer:

a) 1.740 g of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

$\pi r^{2}h$ ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

$r=\frac{d}{2}$

$=\frac{3.36x10^{2}}{2}$

= 168 m

Volume =

$=\frac{22\times 168^{2}\times 21.80}{7}$

$=1.93\times 10^{6} m^{3}$

2.Convert ppm to g/m3 and Solve for mass of F-

$1ppm = 1g/m^{3}$

$0.9ppm = 0.9g/m^{3}$

Because both ppm and g/m3 are same quantity .

$g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}$

$0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}$

$mass\ of\ F- =1.740g$

mass of F- required = 1.740 g

3. Apply mole concept to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

$2Na+F_{2}\rightarrow 2NaF$

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

$\frac {84}{38}\times 1.74$

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0

3 years ago

Hello,

Ulleksa [173]

Answer:

In talc preparation, it is used during the filtration process and also acts as a distribution agent. When it is added to the dill water, it combines with all other compounds present in the substance and leaves the water alone. In this way, it acts as a filtering agent.

Explanation:

it has already been answered

8 0

3 years ago

Read 2 more answers

What are the chemical processes used to make chloroquine?

4vir4ik [10]

You spell Chlorine wrong but the process is called electrolysis

6 0

4 years ago

? + ? = zink chloride + water​

? + ? = zink chloride + water