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3 years ago

ANSWER THESE 3 QUESTION AND I WILL GIVE OUT THE BRAINLIEST

Chemistry

2 answers:

Lana71 [14]3 years ago

6 0

Answer:

A positive acceleration means and increase

A negative acceleration is a decrease

a zero acceleration is a constant movement so its not increasing or decreasing just constant

Explanation:

ladessa [460]3 years ago

4 0

<h2> $\sf \pink{Question}$ </h2>

What is a positive acceleration ?

<h2> $\sf \blue{Answer}$ </h2>

If the velocity of an object increases with time, its acceleration is positive.

<h2 /><h2> $\sf \pink{Question}$ </h2>

What is a zero acceleration ?

<h2> $\sf \blue{Answer}$ </h2>

Zero acceleration is an acceleration, just with zero magnitude. Motion with constant velocity is just a special case of motion with uniform acceleration.

<h2> $\sf \pink{Question}$ </h2>

What is a negative acceleration ?

<h2> $\sf \blue{Answer}$ </h2>

A negative acceleration means you will subtract from the current value of the velocity, and a positive acceleration means you will add to the current value of the velocity. ... And if the acceleration points in the opposite direction of the velocity, the object will be slowing down.

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25.0cm3 of s saturated potassium hydroxide is neutralized by 35.0cm3 of hydrogen chloride acid of concentration 0.75 mol/dm3. Ca

Kamila [148]

Answer:

Concentration of the original $\rm KOH$ solution: approximately $1.05\; \rm mol \cdot dm^{-3}$ .

Explanation:

Notice that the concentration of the $\rm HCl$ solution is in the unit $\rm mol\cdot dm^{-3}$ . However, the unit of the two volumes is $\rm cm^{3}$ . Convert the unit of the two volumes to $\rm dm^{3}$ to match the unit of concentration.

$\begin{aligned} V(\mathrm{NaOH}) &= 25.0\; \rm cm^{3} \\ &= 25.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0250\; \rm dm^{3} \end{aligned}$ .

$\begin{aligned} V(\mathrm{HCl}) &= 35.0\; \rm cm^{3} \\ &= 35.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0350\; \rm dm^{3} \end{aligned}$ .

Calculate the number of moles of $\rm HCl$ molecules in that $0.0350\; \rm dm^{3}$ of $0.75\; \rm mol \cdot dm^{3}$ $\rm HCl\!$ solution:

$\begin{aligned}n(\mathrm{HCl}) &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.00350\; \rm dm^{3} \times 0.75\; \rm mol \cdot dm^{3} \\ &\approx 0.02625\; \rm mol\end{aligned}$ .

$\rm HCl$ is a monoprotic acid. In other words, each $\rm HCl\!$ would release up to one proton $\rm H^{+}$ .

On the other hand, $\rm KOH$ is a monoprotic base. Each $\rm KOH\!$ formula unit would react with up to one $\rm H^{+}$ .

Hence, $\rm HCl$ molecules and $\rm KOH\!$ formula units would react at a one-to-one ratio.

${\rm HCl}\, (aq) + {\rm NaOH}\, (aq) \to {\rm NaCl}\, (aq) + {\rm H_2O}\, (l)$ .

Therefore, that $0.02625\; \rm mol$ of $\rm HCl$ molecules would neutralize exactly the same number of $\rm NaOH$ formula units. That is: $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ .

Calculate the concentration of a $\rm NaOH$ solution where $V(\mathrm{NaOH}) = 0.0250\; \rm dm^{3}$ and $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ :

$\begin{aligned}c(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{V(\mathrm{NaOH})} \\ &= \frac{0.02625\; \rm mol}{0.0250\; \rm dm^{3}}\approx 1.05\; \rm mol \cdot dm^{-3}\end{aligned}$ .

7 0

3 years ago

What is the definition of a chemical bond?

Gnom [1K]

Answer:

Explanation:

bonding is a process of two different atoms sharing electrons for stability and these electrons are attracted by one atom losing it's electrons to another

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3 years ago

Why carbon dioxide can be tested with the help of moist blue litmus paper ?<br>

Evgesh-ka [11]

Answer:

carbon dioxide is acidic and when it comes in contact with blue litmus paper it turns red

Explanation:

4 0

4 years ago

Relatively how much more rapid is the diffusion of hydrogen gas compared to neon gas

Setler79 [48]

A colourless obourless gaseous elements that gives a red Glow in a vacuum tube
A. nonmetallic univalent elements that is normal a colourless

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3 years ago

Describe how functional groups affect an organic molecule's' chemical reactivity

vazorg [7]

Functional groups<span> are set of commonly found </span>groups<span> of atoms covalently bonded to carbon in </span>organic molecules<span>.The unique </span>functional groups<span> present on a bio molecule determine </span>reactivity <span>solubility and other physical </span>properties<span> that lead to its biological role in living organisms.</span>

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3 years ago