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Zinaida [17]
3 years ago
15

What is the minimum number of moles of potassium permanganate that would be required to completely oxidize 1.0 moles of benzalde

hyde?
Chemistry
1 answer:
makvit [3.9K]3 years ago
7 0
Mole ratio :

<span>5 C</span>₆<span>H</span>₆<span>CHO + 2 KMnO</span>₄<span> + 6 H</span>⁺ <span>= 5 C</span>₆<span>H</span>₆<span>COOH + 2 Mn</span>²⁺<span> + 3 H</span>₂<span>O + 2 K</span>⁺

5 moles C₆H₆CHO ------------------ 2 moles KMnO₄
1.0 moles C₆H₆CHO ---------------- ( moles of KMnO₄ )

moles of KMnO₄ = 1.0 x 2 / 5

moles of KMnO₄ = 2 / 5

= 0.40 moles of KMnO4

hope this helps!


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