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Answer:
156 mL will be the new volume of the shape
Explanation:
First of all, we need to convert the Torr to atm.
1220 Torr . 1 atm / 760 Torr = 1.60 atm
When the temperature remains constant, it is satisfied that the volume is modified indirectly proportionally.
Pressure is increased, then volume decreases
Pressure is decreased, then volume increases
P₁ . V₁ = P₂ . V₂
0.768 atm . 325mL = 1.60 atm . V₂
V₂ = 0.768 atm . 325mL / 1.60 atm → 156 mL
There you go. I gave you a image.
Answer:
158.35 K
Explanation:
Using the general gas law
P₁V₁/T₁ = P₂V₂/T₂ where P₁ = 150.4 kPa, V₁ = 12.2 L, T₁ = 22.7 °C = 273 + 22.7 = 295.7 K, P₂ = 101.3 kPa, V₂ = 9.7 L and T₂ = unknown.
Making T₂ subject of the formula, we have
T₂ = P₂V₂T₁/P₁V₁
Substituting the values of the variables into the equation, we have
T₂ = P₂V₂T₁/P₁V₁
T₂ = 101.3 kPa × 9.7 L × 295.7 K/150.4 kPa × 12.2 L
T₂ = 290,557.777 K/1,834.88
T₂ = 158.35 K