45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)
The balanced equation for the reaction is given below:
2Al + 3Cl₂ —> 2AlCl₃
From the balanced equation above,
2 atoms of Al required 3 molecules of Cl₂.
With the above information, we can determine the number of molecules of Cl₂ needed to react with 30 atoms of Al. This can be obtained as follow:
From the balanced equation above,
2 atoms of Al required 3 molecules of Cl₂.
Therefore,
30 atoms of Al will require = 
= 45 molecules of Cl₂.
Thus, 45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)
Learn more: brainly.com/question/24918379
N(Na₂SO₄)=3 mol
n(O)=4n(Na₂SO₄)
n(O)=4*3=12 mol
Density=mass/ volume so you solve for volume and get 461.96 mL
Answer:
40.02 calories
Explanation:
V = 10 mL = 10g
we know t went <em>up</em> by 4°C, this is our ∆t as it is a change.
Formula that ties it together: Q = mc∆t
where,
Q = energy absorbed by water
m = mass of water
c = specific heat of water (constant)
∆t = temperature change
Q = (10 g) x (4.186 J/g•°C) x (4°C)
Q = 167.44 J
Joules to Calories:
167.44 J x 1 cal/4.184 J = 40.02 calories
(makes sense as in image it is close to the value).
Answer:
6
Explanation:
This question is seeking for an equivalent of one expression. The first expression says 1/3 of 12, which means 1/3 × 12 = 4. To find 2/3 of a number that will give us 4, we say
Since; 1/3 of 12 is 4
Then, 4 = 2/3 of x, where x is the number, which when multiplied by two-third (2/3) will result to 4.
4 = 2/3 × x
4 = 2x/3
Cross multiply
2x = 3 × 4
2x = 12
x = 12/2
x = 6.
This means that; 1/3 of 12 = 2/3 of 6
