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butalik [34]
3 years ago
13

A freight train traveled 144 miles in 6 hours. At what rate, in miles per hour, did the train travel?

Mathematics
2 answers:
Maslowich3 years ago
6 0

Answer:

its 24mph

That’s your answer.

LuckyWell [14K]3 years ago
4 0

Answer:

144 mi / 6 hrs = x mi / 1 hr

Cross multiply  

6x=144

X=24

So 24 mi/hr

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if a plane leave the ski resort every hour. the first plane leaves at 10 and the second plane leaves at 4 how man planes leave e
Butoxors [25]
Asked and answered elsewhere.
brainly.com/question/9934382
7 0
3 years ago
What is the answer to > solve 4cos (theta/3) -2 = 0, over [0, 4pi)
Vesna [10]

Hello from MrBillDoesMath!

Answer:  

@ =   pi/3 (or 60 degrees) or @ = 7 pi/3 (or 420 degrees)


Discussion:

Let "@' denote the angle "theta". We are asked to find @ in the interval [0, 4 pi)

where

4cos(@) - 2 = 0.                Adding 2 to both sides

4 cos(@) - 2 +2 = 2  =>

4 cos(@) = 2                     Divide both sides by 4

cos(@) = 2/4 = 0.5


This implies that @ =   pi/3 (or 60 degrees) or @ = (pi/3 + 2pi) = 7 pi/3 (or 420 degrees)


Thank you,

MrB

5 0
3 years ago
An electrician charges ​$35 for the first hour and ​$30 for each additional hour. How much does she charge if it takes her 4 hou
taurus [48]

Answer:

125 I think

Step-by-step explanation:

Multiply 30 x 3 then add 35

Hope it's right

3 0
3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
4 years ago
What is the area of the kite below.
valentina_108 [34]

Answer:

girll how is this college math im in 8th grade and n learned this in 1st grade loll

Step-by-step explanation:

its 15 m I THINK DONT TAKE MY WORD ON IT but tytyty for the points

5 0
3 years ago
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