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4 years ago

If 1=52=103=154=20what does 5 equal?

Physics

1 answer:

iogann1982 [59]4 years ago

7 0

5 would be 25 if it continues in the same pattern

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A car has an initial velocity of 9 km/hr and a final velocity of 66 km/hr. What is the cars average velocity? Use one of the fol

Karolina [17]

Answer:

velocity of 66 km/hr.

Explanation:

7 0

3 years ago

Un cuerpo de 1250 kg se mueve sobre una superficie horizontal por la acción de un mo tor que produce una fuerza de 24500 N. Sabi

bezimeni [28]

The correct answer is b) 7,9 m/s

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3 years ago

A human heart beats once in 0.8 seconds. How many times it will beat in the life of 70 years.

Y_Kistochka [10]

Answer:

Explanation:

108,000 beats per hour

613,200 hours in 70 years

108,000 times 613,200 =

66225600000 beats

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3 years ago

A gas expands at a constant pressure of 3 atm from a volume of 0.02 cubic meters to 0.10 cubic meters. In the process it experie

Nonamiya [84]

a) $2.4\cdot 10^4 J$

For a gas transformation occuring at a constant pressure, the work done by the gas is given by

$W=p(V_f -V_i)$

where

p is the gas pressure

V_f is the final volume of the gas

V_i is the initial volume

For the gas in the problem,

$p=3 atm = 3\cdot 1.013\cdot 10^5 Pa = 3.039\cdot 10^5 Pa$ is the pressure

$V_i = 0.02 m^2$ is the initial volume

$V_f = 0.10 m^3$ is the final volume

Substituting,

$W=(3.039\cdot 10^5 Pa)(0.10 m^3-0.02m^2)=24312 J = 2.4\cdot 10^4 J$

b) $3.24\cdot 10^5 J$

The heat absorbed by the gas can be found by using the 1st law of thermodynamics:

$\Delta U = Q-W$

where

$\Delta U$ is the change in internal energy of the gas

Q is the heat absorbed

W is the work done

Here we have

$\Delta U = 3.0\cdot 10^5 J$

$W=2.4\cdot 10^4 J$

So we can solve the equation to find Q:

$Q=\Delta U + W = 3.0\cdot 10^5 J +2.4\cdot 10^4 J = 3.24\cdot 10^5 J$

And this process is an isobaric process (=at constant pressure).

8 0

3 years ago

How does pressure depend upon force applied?

IRINA_888 [86]

Answer:

Hey mate here's your answer ⤵️

Since pressure depends only on the force acting perpendicular to the surface upon which it is applied, only the force component perpendicular to the surface contributes to the pressure exerted by that force on that surface.

<h2 /><h2>Hope it was helpfulll</h2>

4 0

3 years ago