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navik [9.2K]
3 years ago
7

A^3+5-6(4) HELP FAST I’M IN CLASS

Mathematics
1 answer:
zheka24 [161]3 years ago
7 0
A^3-19 should be the answer, good luck
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I NEED HELP!!!
oksano4ka [1.4K]

Answer:

x= -2, y = -3

Step-by-step explanation:

1. substitute x = 4+2y in the first equation: \begin{bmatrix}2\left(4+2y\right)+y=-7\end{bmatrix}

simplify it : \begin{bmatrix}8+5y=-7\end{bmatrix}

2. isolate y in 8 + 5y = -7 --> 5y = -7 - 8 -->

3. solve for y:  5y = -15 --> y = -15/5 --> y= -3

4. solve for x: x = 4 + 2y

x = 4 + 2(-3)

x = 4 + (-6)

x = -2

6 0
3 years ago
GIVING BRAINLIEST!!!
const2013 [10]

Answer:

answer is A and it feels wierd to answer this

4 0
3 years ago
PLEASE HELP!!!<br><br> it helps alot if you get this correct
Solnce55 [7]

Answer:

A

Step-by-step explanation:

A is the answer

6 0
3 years ago
Read 2 more answers
Mario compared the slope of the function graphed below to the slope of the linear function that has an x-intercept of 1 and a y-
Lelu [443]

Answer:

The slope of the function graphed is less than the linear function that has an x-intercept of 1 and a y-intercept of -2.

Step-by-step explanation:

It is given that x-intercept is 1 and y-intercept is -2.

Now, the coordinate of the point is (1,0) and (0,-2).

We know that,

Slope = \dfrac{y_2-y_1}{x_2-x_1}

S_1=\dfrac{-2-0}{0-1}

S_1 = \dfrac{-2}{-1}

S_1=2

Now, Slope of the graph given

Co-ordinate is (-5,0) and (1,2).

Using the formula of slope

S_2 = \dfrac{2-0}{1-(-1)}

S_2 = \dfrac{2}{1+1}

S_2 = \dfrac{2}{2}

S_2 =1

Now, S_1>S_2

Hence, the slope of function graphed is less than linear function that has an x-intercept of 1 and a y-intercept of -2.

7 0
3 years ago
PLEASE HELP I NEED THE ANSWER ASAP
Andreas93 [3]

Answer:

x>3, the last option with the open circle

Step-by-step explanation:

7 0
3 years ago
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