A^3+5-6(4) HELP FAST I’M IN CLASS
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To answer this question you will set up the proportion shown in the attached picture.
There are 2 ways to solve this.
1. You can create an equivalent ratio by determining the factor that will take you from 1 cm to 2 cm and apply his factor to the 19 miles.
The answer would be 19 x 2= 38 miles for 2 centimeters.
2. The second strategy is to use cross products to get an answer. You multiply the number diagonal from each other. See picture for this work.
There are 2 ways to solve this.
1. You can create an equivalent ratio by determining the factor that will take you from 1 cm to 2 cm and apply his factor to the 19 miles.
The answer would be 19 x 2= 38 miles for 2 centimeters.
2. The second strategy is to use cross products to get an answer. You multiply the number diagonal from each other. See picture for this work.
A. Factor the numerator as a difference of squares:
c. As
, the contribution of the terms of degree less than 2 becomes negligible, which means we can write
e. Let's first rewrite the root terms with rational exponents:
![\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto1%7D%5Cfrac%7B%5Csqrt%5B3%5Dx-x%7D%7B%5Csqrt%20x-x%7D%3D%5Clim_%7Bx%5Cto1%7D%5Cfrac%7Bx%5E%7B1%2F3%7D-x%7D%7Bx%5E%7B1%2F2%7D-x%7D)
Next we rationalize the numerator and denominator. We do so by recalling
In particular,
so we have
For
and 
, we can simplify the first term:
So our limit becomes
c. As
e. Let's first rewrite the root terms with rational exponents:
Next we rationalize the numerator and denominator. We do so by recalling
In particular,
so we have
For
So our limit becomes