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Aloiza [94]
4 years ago
15

How is finding the unit rate helpful before graphing a proportional relationship

Mathematics
1 answer:
Paul [167]4 years ago
4 0
One example, take the conversion fact that there are 5 miles for every 8 km.

Now if we want to work out how many kilometres in 6 miles, the conversion above is not going to help straight away.

We first need to find how many kilometres in ONE mile [which is the unit rate]

5 miles = 8 kilometres
1 mile = 8/5 kilometres
1 mile = 1.6 kilometres

Once we know the unit rate, we can then work out the number of kilometres for any number of miles.

For example:
6 miles = 6×1.6 = 9.6 kilometres
25.5 miles = 25.5 × 1.6 = 40.8 kilometres
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Claire bought some books. One eighth of them are fiction. She has 2 fiction books. How many books does claire have in all.
kirza4 [7]
16 because one eighth is 2 and if u times 2 by 8 because it’s one eighth then u have 16
3 0
3 years ago
Y = f(x + 3) + 3<br> Graph
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Answer:f in the chat

Step-by-step explanation:

4 0
3 years ago
The scale on a map is 1 in. : 15 mi. The distance between two cities is 25 mi. Find the distance in inches between the cities on
fgiga [73]
Create a proportion:

1 in/15 mi= x in/25 mi
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8 0
3 years ago
7/2x+1/2x = 18+ 9/2x
chubhunter [2.5K]

Answer:

x=-36

Step-by-step explanation:

Add the 7/2x +1/2x to be 8/2x which means that it'll be 4x=18=9/2

then subtract 9/2x on both sides so itll be

4x=18+\frac{9}{2} x

-9/2x       -9/2x

-\frac{1}{2} x=18   because if you do 8/2-9/2 it's -1/2

then multiply the reciprocal to both sides so

(\frac{2}{-1})(-\frac{1}{2}x)=(\frac{2}{-1})(18)

which then cancels out -1/2 and makes it

x=-36

4 0
3 years ago
Evaluate the integral. (Use C for the constant of integration.) <br> cos(x) (8 + 7 sin^2(x)) dx
UNO [17]

Answer: 8 \sin x +7(\dfrac{\sin^3x}{3})+C

Step-by-step explanation:

Consider \int \cos(x) (8+7 \sin^2(x)) \, dx

Substitute  t= sinx

then dt = cos x dx

\int \cos(x) (8+7 \sin^2(x)) \, dx = \int (8+7t^2)dt\\\\ =8t+7(\dfrac{t^3}{3})+C

[\int x^ndx=\dfrac{x^{n+1}}{n+1}+C]

=8 \sin x +7(\dfrac{\sin^3x}{3})+C

Hence, \int \cos(x) (8+7 \sin^2(x)) \, dx=8 \sin x +7(\dfrac{\sin^3x}{3})+C

5 0
3 years ago
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