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3 years ago

Help me please thank you

Mathematics

2 answers:

motikmotik3 years ago

7 0

Answer:

I do believe it is the Product of Powers Property.

Step-by-step explanation:

The mathematic definition of a "product" means the outcome of a multiplication problem. And a "power" is the small number at the top of the variable.

Leno4ka [110]3 years ago

3 0

Product of powers property

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maxonik [38]

Approximately 0.67 of a cup of sugar is needed. Let me know if this isn't right.

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2 years ago

What's the slope of the line through each pair of points

aev [14]

Answer:

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Step-by-step explanation:

since both points have a y value of ten the line is vertical, making the line undefined and therefore having no slope.

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3 years ago

IXL geometry please help!

Sedaia [141]

<h3>Answer: 32 degrees</h3>

================================

Work Shown:

Inscribed angle theorem

arc measure = 2*(inscribed angle)

arc ABC = 2*(angle D)

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arc ABC = 70 degrees

-------------

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8 0

3 years ago

The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. (

Vinvika [58]

Answer:

a) $P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

b) $z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

$X \sim N(106,0.3)$

Where $\mu=106$ and $\sigma=0.3$

Part a

We are interested on this probability

$P(X>106.11)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score we got:

$z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

6 0

2 years ago