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stich3 [128]
4 years ago
15

The cycle that is the slowest because there is no gas phase is the _____ cycle.

Physics
2 answers:
madam [21]4 years ago
6 0

Answer: This would be B. Phosphorus

topjm [15]4 years ago
4 0
It would be B. phosphorus
You might be interested in
A 82-kg fisherman in a 112-kg boat throws a package of mass m = 15 kg horizontally toward the right with a speed of vi = 4.8 m/s
abruzzese [7]

Answer:

0.37 m/s to the left

Explanation:

Momentum is conserved.  Initial momentum = final momentum.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

Initially, both the fisherman/boat and the package are at rest.

0 = m₁ v₁ + m₂ v₂

Plugging in values and solving:

0 = (82 kg + 112 kg) v + (15 kg) (4.8 m/s)

v = -0.37 m/s

The boat's velocity is 0.37 m/s to the left.

8 0
3 years ago
Why can we hear sound around a corner but not see light
Viktor [21]

Answer:

Sound waves that we can hear have much longer wavelengths than do light waves. As a result, the diffraction of sound waves around a corner is noticeable and we can hear the sound in the “shadow region,” but the diffraction of light waves around a corner is not noticeable.

Explanation:

i hope that helps :)...<3

8 0
3 years ago
A copper wire has a length of 1.50 m and a cross sectional area of 0.380 mm2. If the resistivity of copper is 1.70 ✕ 10−8 Ω · m
sweet [91]

Answer: 1.044 E -17 A

Explanation:

L =1.50m

A = 0.380mm = 3.8E- 7

Resistivity p =1.70 E-8

R =pl/A

R = 1.70 E-8 × 1.5/ 3.8 E-7

R = 6.71 E-16 ohms

V = IR

0.700 = I × 6.71 E-16

I =1.044E-17 A

5 0
3 years ago
Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
Using the definition of moment of inertia, calculate icm, the moment of inertia about the center of mass, for this object.
Step2247 [10]
<span> The masses have no inertia about their own CM, and "the object" is the two masses. </span>
<span>1. Icm (at point A) = 2mr^2 
hope this helps</span>
3 0
3 years ago
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