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Cerrena [4.2K]
3 years ago
12

A physics student of mass 51.0 kg is standing at the edge of the flat roof of a building, 12.0 m above the sidewalk. An unfriend

ly dog is running across the roof toward her. Next to her is a large wheel mounted on a horizontal axle at its center. The wheel, used to lift objects from the ground to the roof, has a light crank attached to it and a light rope wrapped around it; the free end of the rope hangs over the edge of the roof. The student grabs the end of the rope and steps off the roof.
a. If the wheel has radius 0.300 m and a moment of inertia of 9.60 kg ⋅m^2 for rotation about the axle, how long does it take her to reach the sidewalk?
b. How fast will she be moving just before she lands?
Physics
1 answer:
balandron [24]3 years ago
5 0

Answer:

Explanation:

The wheel and falling student will have common acceleration .

For rotational motion of wheel

Tx r = I α , T is tension in the crank , α is angular acceleration of wheel  , I is moment of inertia , r is radius of the wheel.

= I a / r

T = I a / r²

For motion of student

Mg - T = Ma , M is mass of the wheel.

Mg - I a / r²  = Ma

Mg = Ma +I a / r²

Mg = (M +I  / r²)a

a = Mg / (M +I  / r²)

= 51 x 9.8 / ( 51 + 9.6 / .3² )

499.8 / (51+ 106.67 )

= 499.8 / 157.67

= 3.17 m / s².

If time t is taken to  fall by 12 m

12 = 1/2 a t²

24 / a = t²

24 / 3.17 =t²

t²= 7.57

t = 2.75 s

velocity to reach sidewalk

v = u + at

= 3.17  x 2.75

= 8.72 m / s

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This is best explained through the use of an optics diagram, this is a little too complicated to explain in a short answer, and as I can't draw an appropriate diagram in this answer, I will point you to this excellent resource which explains what you have asked very well!

Go onto the BBC website (you should have access to it even if you aren't in the UK) and paste this after the BBC url,

/bitesize/intermediate2/physics/waves_and_optics/image_formation_from_lens/revision/1/
5 0
3 years ago
A car is pushed with a force of 450 N for 19.4 seconds. What impulse was applied to the car?​
harina [27]

Answer:

impulse = 8820 kg·\frac{m}{s} or 8820 N·s

Explanation:

Impulse J is equal to the average force F_{av} multiplied by the elapsed time Δt or in equation form, J = F_{av}Δt

As long as your force of 450 N is constant then that value is your average force F_{av} and your elapsed time is 19.4 seconds.

Multiply these values.

You will get an impulse of 8820 kg·\frac{m}{s} or 8820 N·s.

6 0
2 years ago
HELP!!! The planet Mars has a mass about one-tenth the mass of Earth. Even though Mars has two moons, their tidal forces have a
vladimir2022 [97]

Answer:

Say: Mars has a much weaker gravity effect than it does because it is smaller and cannot have as much gravity effect than it does on earth.

Explanation:

4 0
3 years ago
If the 80 ohm resistor fails, will the 50 ohm and 100 ohm resistor continue to operate? Why or why not?
sleet_krkn [62]

Answer:

No, the 50 ohm and 100 ohm resistor will not continue to operate.

Explanation:

A closed circuit is the circuit in which there is no break between the negative and the positive end of the battery.

When in this, combinational circuit the 80 ohm resistor fail then there will not any continue supply of current in the circuit due to the breakage because the electron will flow from negative end of the battery to positive end if their is no breaking in the circuit.

Therefore the 50 ohm and 100 ohm circuit will not continue to operate because of the breaking of the circuit and current will not flow.

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3 years ago
One hundred turns of insulated copper wire are wrapped into a circular coil of crosssectional area 1.20⇥103 m2. The two ends of
arsen [322]

Answer:

236.3  x 10^-^3 C

Explanation:

Given:

B(0)=1.60T and B(t)=-1.60T

No. of turns 'N' =100

cross-sectional area 'A'= 1.2 x 10^-^3m²

Resistance 'R'= 1.3Ω

According to Faraday's law, the induced emf is given by,

ℰ=-NdΦ/dt

The current given by resistance and induced emf as

I = ℰ/R

I= -NdΦ/dtR

By converting the current to differential form(the time derivative of charge), we get

\frac{dq}{dt}=  -NdΦ/dtR

dq= -N dΦ/R

The change in the flux dФ =Ф(t)-Ф(0)

therefore, dq = \frac{N}{R} (Ф(0)-Ф(t))

Also, flux is equal to the magnetic field multiplied with the area of the coil

dq = NA(B(0)-B(t))/R

dq= (100)(1.2 x 10^-^3)(1.6+1.6)/1.3

dq= 236.3  x 10^-^3 C

5 0
3 years ago
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