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Usimov [2.4K]
3 years ago
11

Help me pleaseeee 5^4z-13 = 125

Mathematics
1 answer:
elena-s [515]3 years ago
6 0
Z= 138/625 or in decimal form it’s 0.2208
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Diego says that the product of 0.51 x 2.427 will have five decimal places. is Diego correct.
zlopas [31]
Yes. There are 2 decimal places in .51 and 3 in 2.427. 
So there would be a total of 5 decimal places.
5 0
4 years ago
Read 2 more answers
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
Arah has a floor plan of a room that is 5 inches wide and 6 inches long. The scale of the floor plan is
Vitek1552 [10]

Answer:

The answer is C.

Hope this helps!

8 0
3 years ago
How to solve this question
VMariaS [17]
<span>The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

<span>\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2

Since variance has to be 14, we set \sigma^2  = 14 and solve for m

14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\&#10;14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\&#10;0 = \frac{-88}{9}  -\frac{14}{9}m + \frac{2}{9}m^2&#10;

quadratic formula


m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\&#10;m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \frac{10}{3}  }{\frac{4}{9} } \\&#10;m = 11, -4

-4 doesnt' work as it is not a positive integer

m = 11


</span></span>
5 0
3 years ago
HELP
Serjik [45]

Answer:

A: 5+7+2.5=14.5/3=4.8333333

B: 6+12+3.5=21.5/3=7.16666666

4 0
3 years ago
Read 2 more answers
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