Hold up I need to ask my older brother to help with this one
Answer:
a. P(AnB)
b. P(B|A)
c. 
d. P(A or B)
e. 
Step-by-step explanation:
Since A= driver is under 25 years old (1)
B = driver has received a speeding ticket (2)
a.The probability the driver is under 25 years old and has recieved a speeding ticket.
this simple means the intersection of both set, which can be written as
P(AnB)
b. The probability a driver who is under 25 years old has received a speeding ticket.
This is a conditional probability, probability that B will occur given that A as occur.
P(B|A)
c. the probability a driver who has received a speeding ticket is 25 years or older.

d. The probability the driver is under 25 years old or has received a speeding ticket.
P(A or B)
e. The probability the driver is under 25 years old or has not received a speeding ticket.

Answer:
2/5m - 1/5
Step-by-step explanation:
distribute the 2 to every term in ()
2(1/5m-2/5) = 2/5m - 4/5
now you have 2/5m -4/5 +3/5
combine like terms variables with variables, non- variables with non-variables. -4/5 + 3/5 = 1/5
2/5m - 1/5
First multiply 2x - 5 by 3 amd will open the brackets
3(2x-5)-4=33
6x - 15 - 4 = 33
6x - 19 = 33
Take -19 to other side and its sign will be become +
6x = 33 + 19
6x = 52

x = 8.6