2x + 4(x - 1) = 2 + 4x
2x + 4x - 4 = 2 + 4x
6x - 4 = 2 + 4x
6x - 4x = 2 + 4
2x = 6
x = 3........there is 1 solution
25 - x = 15 - (3x + 10)
25 - x = 15 - 3x - 10
25 - x = -3x + 5
3x - x = 5 - 25
2x = - 20
x = -20/2
x = -10.....there is 1 solution
4x = 2x + 2x + 5(x - x)
4x = 4x + 5x - 5x
4x = 4x......this has infinite solutions
learn this...
if ur equation ends in a variable equaling a number, then there is one solution.
if ur equation ends in something not equal, like 2 = 4, or 4 = 6, then there is 0 solutions.
if ur equation ends in something equal to something,(the same) like 2 = 2, or 4x = 4x, then there is infinite solutions
2 Times + 2 =4 table of a pair
Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:
(x - 2)(x + 3) 10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²
Answer: LCM is 10(x - 2)(x + 3)²
Solving for X.
5 = 2x^2 + 3 Subtract 3 from both sides.
2 = 2x^2 Divide by 2 on both sides.
1 = x^2 Take the square root of both sides.
X = 1
Answer:
Step-by-step explanation:
1.
Equation one:
x = -5, x = -1 (Both are real)
Equation two:
No real solutions
Equation three:
x = -3 (Real)
Equation four:
No real solutions
2.
The easiest way to figure out if an equation has real solutions is to factor it. If it is factorable, then it has real solutions. If it isn't, then it doesn't have real solutions.
