Question

Two charges Q1 = +4 nC (positive) and Q2 = -2 nC (negative) are arranged in a line. Q1 is at the origin (x-0) and Q2 is at x=4 m. What is the electric field at the point x 1 m on the same line? Let sign of the electric field indicate the direction; positive is towards larger x and negative is towards smaller x. 38 N/C 13.5 N/C 4.5 N/C 34 N/C

Answer 1

Answer:

Explanation:

Field due to a charge = k x Q / d²

field due to positive charge

=9 x 10⁹ x 4 x 10⁻⁹ / 1x1 = 36 N/C in positive x -direction.

Field due to negative charge

= 9 x 10⁹ x 2 10⁻⁹ / 3² = 2 N/C in positive x-direction.

Total field = 36 +2 = 38 N/C .