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V125BC [204]
3 years ago
14

The image shows an electromagnet made with a 1.5-volt battery how would the magnetic field be affected if you replaced its 1.5-v

olt battery (on the left) with a 9-volt battery (shown on the right) while using the same nail and coil?
A. The magnetic field strength would increase
B. The magnetic field would not be affected by this change
C. The magnetic field strength would decrease
D. The magnetic field would change direction more frequently

Physics
2 answers:
Neporo4naja [7]3 years ago
8 0
A.
____________________
nignag [31]3 years ago
4 0
Well It would increase(A), because the volts for each of the batteries are different.  So the higher the Volt of the battery the stronger it'll be. So in this situation the 9 Volt Battery (The second image to the right) would have a stronger effect of the magnetic field. I hope this helps:3 Answer- A. 
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A 1-kg rock is suspended from the tip of a horizontal meterstick at the 0-cm mark so that the meterstick barely balances like a
tigry1 [53]

Explanation:

Given that,

Mass if the rock, m = 1 kg

It is  suspended from the tip of a horizontal meter stick at the 0-cm mark so that the meter stick barely balances like a seesaw when its fulcrum is at the 12.5-cm mark.

We need to find the mass of the meter stick. The force acting by the stone is

F = 1 × 9.8 = 9.8 N

Let W be the weight of the meter stick. If the net torque is zero on the stick then the stick does not move and it remains in equilibrium condition. So, taking torque about the pivot.

9.8\times 12.5=W\times (50-12.5)\\\\W=\dfrac{9.8\times 12.5}{37.5}

W = 3.266 N

The mass of the meters stick is :

m=\dfrac{W}{g}\\\\m=\dfrac{3.266}{9.81}\\\\m=0.333\ kg

So, the mass of the meter stick is 0.333 kg.

5 0
3 years ago
A time-varying horizontal force F(t) = At4 + Bt2 acts for 0.500 s on a 12.25-kg object, starting attime t = 1.00 s. In the SI sy
PSYCHO15rus [73]

Answer:

3.82 Ns

Explanation:

Time varying horizontal Force is given as

F(t) = A t⁴ + B t²

F(t) = 4.50 t⁴ + 8.75 t²

Impulse imparted is given as

I = \int_{0}^{t}Fdt

I = \int_{0}^{1}Fdt

I = \int_{0}^{1}(4.50 t^{4} + 8.75 t^{2})dt

I = ((0.9) (1)^{5} + (2.92) (1)^{3})

I = 3.82 N-s

7 0
3 years ago
Read 2 more answers
Jupiter and Saturn each have the same three basic cloud layers, but the spacing of the layers differs on the two planets. Why is
-Dominant- [34]

Answer:

b. Jupiter’s greater gravity has compressed the layers, so they are closer together there.

Explanation:

The value for Jupiter mass is 1.8981×10²⁷kg, while the mass of Saturn is 5.6832×10²⁶kg, so the different layers of clouds in Jupiter will be submitted to a greater gravitational pull because it has a bigger mass, as is established in the law of universal gravitation:

F = G\frac{m1m2}{r^{2}}   (1)

Where m1 and m2 are the masses of two objects, G is the gravitational constant and r is the distance between the two objects.

As it can be seen in equation 1, the gravitational force is directly proportional to the product of the masses of the objects, so if the mass increase the gravitational force will do it too.  

For the case of Saturn, it has a lower mass so its layers of clouds will suffer a weaker gravitational pull. That leads to the three clouds being more spacing that the ones of Jupiter.    

3 0
3 years ago
You drive a car 640 m to the east, then 340 m to the north what is the magnitude of your displacement
mixer [17]

Magnitude of displacement = \sqrt{640^2 + 340^2}

Adding the squares gives displacement = \sqrt{525,200}

Displacement =  \sqrt{525,200} ≈ 724.7m

6 0
3 years ago
1. What did you observe about the magnitudes of the forces on the two charges? Were they the same or different? Does your answer
Aloiza [94]

Answer:

Following are the solution to the given question:

Explanation:

Its strength from both charges is equivalent or identical. The power is equal. And it is passed down

F=\frac{kq_1q_2}{r^2}

Therefore, the extent doesn't rely on the fact that charges are the same or different. Newton's third law complies with Electrostatic Charges due to a couple of charges. They are similar in magnitude, and they're in the other way.

|F_{12}| = |F_{21}|

7 0
3 years ago
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