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V125BC [204]
3 years ago
14

The image shows an electromagnet made with a 1.5-volt battery how would the magnetic field be affected if you replaced its 1.5-v

olt battery (on the left) with a 9-volt battery (shown on the right) while using the same nail and coil?
A. The magnetic field strength would increase
B. The magnetic field would not be affected by this change
C. The magnetic field strength would decrease
D. The magnetic field would change direction more frequently

Physics
2 answers:
Neporo4naja [7]3 years ago
8 0
A.
____________________
nignag [31]3 years ago
4 0
Well It would increase(A), because the volts for each of the batteries are different.  So the higher the Volt of the battery the stronger it'll be. So in this situation the 9 Volt Battery (The second image to the right) would have a stronger effect of the magnetic field. I hope this helps:3 Answer- A. 
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A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and
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The upward force exerted on the board by the support is 530.8 N.

<h3>Upward force exerted on the board by the support</h3>

The sum of the upward forces is equal to sum of downward forces;

total downward forces = 52.8 N + 206 N + 272 N = 530.8 N

downward force = upward force = 530.8 N

Thus, the upward force exerted on the board by the support is 530.8 N.

Learn more about upward force here: brainly.com/question/6080367

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2 years ago
Emily’s vacuum cleaner has a power rating of 200 watts. If the vacuum cleaner does 360,000 joules of work,
gtnhenbr [62]
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4 years ago
Two identical bullets are used. Both are released at the same height - one fired out of a gun, the other is dropped. Ignoring ai
irina [24]

Answer:

Both bullets will hit the ground at the same time.

Explanation:

Let's only analyze the vertical problem.

Any object that is not in the floor or resting in some site is being affected by the gravitational force (remember that we are ignoring air resistance)

Then the acceleration of this object will be equal to the gravitational acceleration:

a = -9.8m/s^2

Where the minus sign is because this acceleration goes down.

To get the velocity equation we need to integrate over time, we will get:

v(t) = ( -9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity.

To get the position equation we need to integrate over time again, we will get:

p(t) = (1/2)*( -9.8m/s^2)*t^2 + v0*t + H

Where H is the initial height.

p(t) = (-4.9 m/s^2)*t^2 + v0*t + H

The object will hit the ground when p(t) = 0

Then we need to solve for t the next equation:

(-4.9 m/s^2)*t^2 + v0*t + H = 0

Notice that the only things we need to know are:

H = initial height (we know that is the same for both bullets)

v0 = initial vertical velocity (also is the same for both bullets)

Notice that the horizontal velocity does not affect this equation, then we will get the same value of t for the dropped bullet and for the fired bullet.

This means that both bullets will hit the ground at the same time.

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3 years ago
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It's simple.
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