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V125BC [204]
3 years ago
14

The image shows an electromagnet made with a 1.5-volt battery how would the magnetic field be affected if you replaced its 1.5-v

olt battery (on the left) with a 9-volt battery (shown on the right) while using the same nail and coil?
A. The magnetic field strength would increase
B. The magnetic field would not be affected by this change
C. The magnetic field strength would decrease
D. The magnetic field would change direction more frequently

Physics
2 answers:
Neporo4naja [7]3 years ago
8 0
A.
____________________
nignag [31]3 years ago
4 0
Well It would increase(A), because the volts for each of the batteries are different.  So the higher the Volt of the battery the stronger it'll be. So in this situation the 9 Volt Battery (The second image to the right) would have a stronger effect of the magnetic field. I hope this helps:3 Answer- A. 
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Put the following steps for calculating net worth in the correct order.
uysha [10]
Answer:

Step 1: List you assets

Step 2: List your liabilities

Step 3: Subtract your liabilities from your
assets

Step 4: Total your assets

Step 5: Total your liabilities
4 0
3 years ago
An object is placed to the left of a convex mirror, such that the object-to-image distance is 140 cm.
labwork [276]

Answer:

The focal length of the mirror is 52.5 cm.

Explanation:

Given that,

Object to Image distance d = 140 cm

Image distance v= 35 cm

We need to calculate the object distance

u = d-v

u = 140-35=105\ cm

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{-105}+\dfrac{1}{35}

\dfrac{1}{f}=\dfrac{2}{105}

f=52.5\ cm

Hence, The focal length of the mirror is 52.5 cm.

6 0
3 years ago
If the airman had a mass of 80 kg, find the magnitude of the air drag acting on him when he reached terminal velocity of 54 m/s
Vlad1618 [11]

The magnitude of the air drag is 784 N

Explanation:

An object falling down reaches the terminal velocity when the magnitude of the air drag acting on it becomes equal to the weight of the object. Mathematically, this condition can be written as:

F_D = mg

where

F_D is the magnitude of the air drag

m is the mass of the object

g is the acceleration of gravity

In this problem, we have

m = 80 kg is the mass of the airman

g=9.8 m/s^2 is the acceleration of gravity

Substituting into the formula, we find:

F_D = (80)(9.8)=784 N

Learn more about forces here:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0
3 years ago
E asteroid belt circles the sun between the orbits of mars and jupiter. one asteroid has a period of 6.0 earth years. part a wha
anzhelika [568]

To solve the problem, use Kepler's 3rd law : 

T² = 4π²r³ / GM 

Solved for r : 

r = [GMT² / 4π²]⅓ 

but first covert 6.00 years to seconds : 

6.00years = 6.00years(365days/year)(24.0hours/day)(6... 
= 1.89 x 10^8s 

The radius of the orbit then is : 

r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.89 x 10^8s)² / 4π²]⅓ 
= 6.23 x 10^11m

6 0
3 years ago
If a rock has a density of 2g/cm³ and a volume of 8cm³, what is its mass?
Yakvenalex [24]
Density=mass÷volume
mass=density×volume
mass=2×8=16 g
3 0
3 years ago
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