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V125BC [204]
3 years ago
14

The image shows an electromagnet made with a 1.5-volt battery how would the magnetic field be affected if you replaced its 1.5-v

olt battery (on the left) with a 9-volt battery (shown on the right) while using the same nail and coil?
A. The magnetic field strength would increase
B. The magnetic field would not be affected by this change
C. The magnetic field strength would decrease
D. The magnetic field would change direction more frequently

Physics
2 answers:
Neporo4naja [7]3 years ago
8 0
A.
____________________
nignag [31]3 years ago
4 0
Well It would increase(A), because the volts for each of the batteries are different.  So the higher the Volt of the battery the stronger it'll be. So in this situation the 9 Volt Battery (The second image to the right) would have a stronger effect of the magnetic field. I hope this helps:3 Answer- A. 
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Cathode-ray tubes produce images on the principle of induced emf. true or false?
yan [13]
The appropriate response is false. Cathode-beam ray does not deliver pictures on the guideline of instigated emf. The cathode-ray is a high-vacuum tube in which cathode beams deliver an iridescent picture on a fluorescent screen, utilized mostly in TVs and workstations.
3 0
3 years ago
The tires of a car support the weight of a stationary car. If one tire has a slow leak, the air pressure within the tire will __
Kipish [7]

Answer:

The tires of a car support the weight of a stationary car. If one tire has a slow leak, the air pressure within the tire will decrease with time, the surface area between the tire and the road will increase with time, and the net force the tire exerts on the road will be constant with time.

Explanation:

when a wheel has an air leak, it means that the inside of the tire has less air, which means that there will be less air pushing the walls of the tire so that the air pressure decreases.

On the other hand, the tire begins to deform due to lack of air which increases the area of ​​contact with the floor.

As the weight of the car remains constant and the air has a negligible mass the force towards the road will be the same

4 0
4 years ago
A 480 g falcon reaches a speed of 75 m/s in a vertical dive. if we assume that the falcon speeds up under the influence of gravi
poizon [28]

Answer:

286.7 m

Explanation:

So we are assuming the PE of the falcon is converted to KE

KE = PE

1/2 (.480)(75)^2 = .480 (9.81)(h )    solve for h = 286.7 m

8 0
2 years ago
An electron is ejected from the cathode by a photon with an energy slightly greater than the work function of the cathode. How w
Ksivusya [100]

It will be approximately equal.

<h3>How will the final kinetic energy change?</h3>

We can infer that all of the energy in the electron is Potential energy (PE) because the energy provided by the photon is hardly enough to outweigh the work function.

It will gain kinetic energy (KE) as it advances in the direction of the anode because it is moving through an electric field. All of the PE will have been transformed to KE by the time it reaches the anode.

According to the question

K = hf - W

W = Work function

The energy of photons is comparable. After conversion, there was only a little amount of KE remaining.

Therefore, PE (W) essentially equals KE (K).

It will about be equal.

Learn more about work function here:

brainly.com/question/19595244

#SPJ4

3 0
2 years ago
At 1.70 atm, a sample of gas takes up 4.25L. If the pressure in the gas is increased to 2.40 atm, what will the new volume be?
ozzi

Answer:

This question is an example of Boyle's gas law which states that the pressure of a given mass of a gas is inversely proportional to its volume at a constant temperature. The formula for this gas law is:

P1·V1 = P2·V2

P1 = initial pressure = 1.7 atm

V1 = initial volume = 4.25 L

P2 = final pressure = 2.4 atm

V2 = final volume = ?

Rearrange the formula to isolate V2. Substitute the known data and solve.

V2 = P1·V1/P2

V2 = 1.7 atm·4.25 L/2.4 atm = 3.0 L to two significant figures

The new volume will be ~3.0 L.

Explanation:

3 0
4 years ago
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