Peyton and her children went into a restaurant and where they sell drinks for $3 each
2 answers:
Answer: 6 ≤ x ≤ 7
Step-by-step explanation:
Let x represent the number of tacos that she could buy.
If Peyton decided to buy 4 drinks and he must buy at least 10 drinks and tacos altogether, it means that
x + 4 ≥ 10
x ≥ 10 - 4
x ≥ 6
The restaurant sells drinks for $3 each and tacos for $4 each. If Peyton has $40 to spend, it means that
3 × 4 + 4x ≤ 40
12 + 4x ≤ 40
4x ≤ 40 - 12
4x ≤ 28
x ≤ 28/4
x ≤ 7
Therefore, the possible values for
the number of tacos that she could buy is
6 ≤ x ≤ 7
Answer:
6, 7
Step-by-step explanation:
Drinks cost= $3*4=$12
Remaining amount=$28
Maximum number of tacos that can be bought=$28÷4=7
Min number of Tacos=10-4=6
Possible values are between 6 and 7. Hence 6, 7.
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