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Genrish500 [490]
2 years ago
12

Why it is very important to follow the steps in solving an equation with 2 or more operations involve?

Mathematics
1 answer:
rusak2 [61]2 years ago
8 0
Yeah but I said the answer is yes because of the color
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What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
My little brother asked for help and I don't even understand it. Can someone explain this for us?
frozen [14]
1. NIL
2. ZERO
3. OH
4. NOUGHT
5. LOVE

Hope this helps!
6 0
3 years ago
Read 2 more answers
A large swimming pool has a perimeter of 1,004 meters, this rectangular-shaped pool is 40 meters longer than 5 times its width.
ANEK [815]
Width is 996 hope its right only in 9th soooooo
4 0
3 years ago
Grading managers. Some companies "grade on a bell curve" to compare the performance of their managers and professional workers.
Monica [59]

Answer:

\mu = 250, \sigma = 175.781

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the grades of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

For this case we have two conditions given:

P(X

P(X>475) = 0.1 or equivalently P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

So we can find a value from the normal standard distribution that accumulates 0.1 and 0.9 of the area in the left, for this case the two values are:

z= -1.28, z=-1.28

We can verify that P(Z<-1.28) =0.1[/tex] and P(Z<1.28) =0.9[/tex]

And then using the z score we have the following formulas:

-1.28 = \frac{25 -\mu}{\sigma}   (1)

1.28 = \frac{475 -\mu}{\sigma}   (2)

If we add equations (1) and (2) we got:

\frac{25 -\mu}{\sigma} + \frac{475 -\mu}{\sigma} =0

We can multiply both sides of the equation by \sigma and we got:

25+ 475 -2 \mu = 0

\mu = \frac{500}{2}= 250

And then we can find the standard deviation for example from equation (1) and we got:

\sigma = \frac{25-250}{-1.28}=175.781

So then the answer would be:

\mu = 250, \sigma = 175.781

 

3 0
3 years ago
3[x + 3(4x – 5)] = 15x – 24
Alex17521 [72]

Answer:

\boxed{ \bold{ \huge{ \boxed{  \sf{x = 0.875}}}}}

Step-by-step explanation:

\sf{3[ x + 3(4x - 5)]  = 15x - 24}

Distribute 3 through the parentheses

⇒\sf{3[ x + 12x - 15 ]  = 15x - 24}

Collect like terms : 12x and x

⇒\sf{3[ 13x - 15 ]  = 15x - 24}

Distribute 3 through the parentheses

⇒\sf{39x - 45 = 15x - 24}

Move 15x to left hand side and change it's sign

Similarly, move 45 to right hand side and change it's sign

⇒\sf{39x - 15x =  - 24 + 45}

Collect like terms

⇒\sf{24x =  - 24 + 45}

Calculate

⇒\sf{24x = 21}

Divide both sides of the equation by 24

⇒\sf{ \frac{24x}{24}  =  \frac{21}{24}}

Calculate

⇒\sf{x = 0.875}

Hope I helped!

Best regards! :D

5 0
3 years ago
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