All categories

2 years ago

________ is a condition in an experiment that remains the same.

Biology

1 answer:

pychu [463]2 years ago

3 0

Answer: Constants

Explanation:

You might be interested in

Grizzly bears: As predators, bears eat several species, like moose and elk. They also eat many fruits throughout the ecosystem.

Anuta_ua [19.1K]

Your teacher likes to copy. Found this at https://examples.yourdictionary.com/examples-of-keystone-species.html

Grizzly bears: As predators, bears keep down the numbers of several species, like moose and elk. They also carry and deposit seeds throughout the ecosystem. Bears that eat salmon will leave their dropping and the partially eaten remains that provide nutrients such as sulfur, nitrogen and carbon to the soil.

6 0

2 years ago

Select all of the answers that apply.

Paraphin [41]

The four laws or principles that are involved with the study of Stratigraphy are the following:
1. Principle of original horizontality
2. Law of superposition
3. Law of crosscutting relationships
4. Principle of Lateral Continuity
5. Principle of Faunal Succession
6. The Law of inclusions
Therefore, the correct answers would be 1, 2 and 4. Hope this answer helps.

3 0

2 years ago

Which group of protists to euglena belong to?

hjlf

Euglena are a unicellular organism. They are classified into the Kingdom Protista. They are then further classified into the Phylum<span> Euglenophyta. All euglena can make their own food by photosynthesis.</span>

5 0

3 years ago

In hamsters, we can examine the genes for coat color and eye color which are linked:B = brown coat, b = white coat, G = green ey

Inessa [10]

Answer:

10.2 cM

Explanation:

Given,

pure breeding parent 1 : BBgg = brown coat and pink eyes

pure breeding parent 2 : bbGG = white coat and green eyes

BBGG X bbgg = F1 = BbGg ( All are brown with green eyes )

When F1 progeny is test crossed with white coat and pink eyes hamster:

BbGg X BbGg = F2 =

brown, pink eyes = 99 = parental

white, green eyes = 103 = parental

brown, green eyes = 12 = recombinant

white, pink eyes = 11 = recombinant

Recombination frequency =

(total number of recombinants / total progeny ) * 100

= [( 11 + 12 ) / ( 99 + 103 + 12 + 11 )] * 100 = (23/225)*100 = 0.102 * 100 = 10.2 %

1 % recombination frequency = 1 cM distance between genes

Hence, the distance between B and G gene is 10.2 cM

4 0

3 years ago

How do scientists identify plate boundaries

morpeh [17]

Volcanic activity
fault lines
mnt. ranges
and siesmagraphs

3 0

3 years ago

Read 2 more answers