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Finger [1]
3 years ago
10

How many solutions does the equation ?3y + 3y + 4 = 4 have? None Infinitely many One Four

Mathematics
2 answers:
Damm [24]3 years ago
8 0

Answer:

none

Step-by-step explanation:

3y+3y+4=4

6y+4(-4)=4(-4)

6y=0

0/6=

aksik [14]3 years ago
6 0

3y + 3y + 4 = 4

Convert to the form ax = b

3y + 3y = 4 - 4

6y = 0

y = 0

<h2>One solution</h2>
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What is the solution to this equation log(2x-100)=3
Mnenie [13.5K]
Greeting to you! My name is Cecille and I’m here to answer that question

For more explanation, please see the attachment

5 0
1 year ago
paris run 3 1/2 laps around the circular track in the school gym. The track has a diameter of 1/2 mile. About how far does paris
fiasKO [112]

Answer:

5.497787144 miles

Step-by-step explanation:

Remember that circumference of a circle can be calculated with:

2\pi r

r=radius

We also know that the radius is just a half of the diameter.

So, the radius of the track is (1/2)/2=1/4 miles

Now, use the circumference of a circle formula to find how much she runs in 1 lap.

2\pi (\frac{1}{4} )

Simplify

\frac{\pi }{2}

This is how much she runs in 1 lap.

Multiply by 3.5 for 3 and a half laps.

\frac{\pi }{2}*3.5

The answer is around 5.497787144 miles.


7 0
3 years ago
The fish population in a certain lake rises and falls according to the formula F = 3000(23 + 11t − t2). Here F is the number of
Gemiola [76]

Answer:

a) On January 1, 2017 the fish population will be the same as the initial population.

b) On September 18th, 2018 the fish population will be zero.

Step-by-step explanation:

Hi there!

a) First, let´s write the function:

F(t) = 3000(23 + 11t − t²)

The population on January 1, 2006 is the population at t = 0. Then:

F(0) = 3000(23 + 11· 0 - 0²)

F(0) = 3000 · 23 = 69000

This will be the population every time at which t² - 11t = 0. Then let´s find the other value of t (besides t = 0) that makes that expression to be zero:

t² - 11t = 0

t(t - 11) = 0

t = 0

and

t - 11 = 0

t = 11

On January 1, 2017 (2006 + 11), the fish population will be the same as the initial population.

b) We have to obtain the value of t at which F(t) = 0

F(t) = 3000(23 + 11t − t²)

0 = 3000(23 + 11t − t²)

divide both sides of the equation by 3000

0 = 23 + 11t − t²

Let´s solve this quadratic equation using the quadratic formula:

a = -1

b = 11

c = 23

x = [-b ± √(b² - 4ac)] / 2a

x = 12.8  ( the other value of x is negative and therefore discarded).

After 12.8 years all the fish in the lake will have died.

If 1 year is 12 months, 0.8 years will be:

0.8 years · 12 months/year = 9.6 months

If 1 month is 30 days, 0.6 month will be:

0.6 month · 30 days / month = 18 days

All the fish will have died after 12 years, 9 months and 18 days from January 1, 2006. That is, on September 18th, 2018.

7 0
3 years ago
Which equation can be used to solve the problem?<br><br> 750 is 150 percent of what?
Juli2301 [7.4K]

150750 × 100100 = 20100 = 20%

If you are using a calculator, simply enter 150÷750×100 which will give you 20 as the answer.


5 0
3 years ago
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Rashid [163]
The first option is correct (-x)
4 0
3 years ago
Read 2 more answers
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