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3 years ago

6u-2u+4 simplified please

Mathematics

2 answers:

lubasha [3.4K]3 years ago

8 0

Answer:

4u+4

Step-by-step explanation:

olga_2 [115]3 years ago

6 0

Answer:

4u+4

Step-by-step explanation:

6-2+4

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Answer:

Test statistic Z= 0.13008 < 1.96 at 0.10 level of significance

null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women

Step-by-step explanation:

<em>Step(I)</em>:-

Given surveyed two random samples of 390 men and 360 women who were tested

first sample proportion

$p_{1} = \frac{360}{390} = 0.9230$

second sample proportion

$p_{2} = \frac{47}{52} = 0.9038$

Step(ii):-

Null hypothesis : H₀ : There is no difference proportion of positive tests among men is different from the proportion of positive tests among women

Alternative Hypothesis:-

There is difference between proportion of positive tests among men is different from the proportion of positive tests among women

$Z = \frac{p_{1}- p_{2} }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} } } }$

where

$P = \frac{n_{1}p_{1} +n_{2} p_{2} }{n_{1}+n_{2} }$

P = 0.920

$Z= \frac{0.9230-0.9038}{\sqrt{0.920 X0.08(\frac{1}{390}+\frac{1}{52} } )}$

Test statistic Z = 0.13008

Level of significance = 0.10

The critical value Z₀.₁₀ = 1.645

Test statistic Z=0.13008 < 1.645 at 0.1 level of significance

Null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women

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