Evaluate the following, expressing your answer as a decimal: 3/8 - -0.2
1 answer:
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Answer:
114 degrees
Step-by-step explanation:
Hi there.
Line segment LN is a straight line, meaning that it contains a straight angle (an angle measuring 180 degrees).
We know that if this is a straight angle, that .
Therefore, m∠x = 114 degrees.
Hope this helps! :^)
Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere
The differential of V with respect to r is:
dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
To solve this, we have to find the volume of the cylinder first. The formula to be used is 
Given:V= ?r= 6cmh= 10cm
Solution:
V= (3.14)(6cm)
x 10cmV= (3.14)(
) x 10cmV= (
) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
Given:V= ?r= 6cmh= 10cm
Solution:
V= (3.14)(6cm)
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.