Question

PLS HELP ASAP :DDDDDDDDDDDDDDDDDDD

Answer 1

Pythagoras in HBC : $HC=\sqrt{HB^2-BC^2}=\sqrt{20^2-12^2}=16in$

Pythagoras in HDC : $HD=\sqrt{HC^2-CD^2}=\sqrt{16^2-14^2}\approx\boxed{7.7 in}$