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A 25 Ω resistor has a voltage drop of 12 V across it. Calculate the current flowing through the resistor
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Hello there,
You should know the <span>solubility of AgNO3 in water at 20°C equals to 2220 g/L.
So we can say that in 1 L of water, 2220 g of AgNO3 can be dissolve.
Now you should know 1L = 1000g.
Which means 1000 g of water can dissolve 2220 g of AgNO3.
Therefore :
</span>250 g<span> --> x
1000 g --> 2220 g
So : </span>
.
In short, 555g of AgNO3 can be dissolved in 250g of water at 20°C.
Hope this helps !
Photon
You should know the <span>solubility of AgNO3 in water at 20°C equals to 2220 g/L.
So we can say that in 1 L of water, 2220 g of AgNO3 can be dissolve.
Now you should know 1L = 1000g.
Which means 1000 g of water can dissolve 2220 g of AgNO3.
Therefore :
</span>250 g<span> --> x
1000 g --> 2220 g
So : </span>
In short, 555g of AgNO3 can be dissolved in 250g of water at 20°C.
Hope this helps !
Photon