Bellow you my find the chemical equations of the ionization of a triprotic acid.
Explanation:
The chemical equations for the ionization of phosphoric acid (H₃PO₄), which is a triprotic acid, in water:
H₃PO₄ (s) + H₂O (l) → H₂PO₄⁻ (aq) + H₃O⁺ (aq)
H₂PO₄⁻ (aq) + H₂O (l) → HPO₄²⁻ (aq) + H₃O⁺ (aq)
HPO₄²⁻ (aq) + H₂O (l) → PO₄³⁻ (aq) + H₃O⁺ (aq)
where:
(s) - solid
(l) - liquid
(aq) - aqueous
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triprotic acid
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1) 2K(s) + 2H₂O(l)→ 2KOH(aq) + H₂<span>(g)
This is a single replacement reaction where K reacts with H</span>₂O , displaces the H⁺ ion in water and combines with OH⁻ to form a base.
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2) 2B</span>i(NO₃)₃(aq) + 3H₂S(g)→ Bi₂S₃(s) + 6HNO₃<span>(aq)
</span>This is a double displacement reaction where the ions are exchanged and form new compounds. Since ions are exchanged between 2 compounds its called double displacement.
3) 2HNO₃<span>(aq) + Ba(OH)</span>₂<span> → Ba(NO</span>₃<span>)</span>₂<span>(aq) + 2H</span>₂O<span>(l)
This is an acid base reaction where nitric acid and barium hydroxide react to form the respective salt and water</span>
The temperature of internal organs of a dead body and the environmental temperature at the scene of death are important to consider in determining the time of death.
Answer:
I think it's b.
Explanation:
Because solubility increased by temperature.
The answer is heterogeneous