1. Sugar refers to easily metabolized carbohydrate; sweetener is an additive that is added to foods for the sweetening effect
2. Sugar in all its forms does not require authentication; sweeteners need to be approved by an accreditation body or the EU
3. Sugar is caloric, while sweeteners can be caloric or non caloric in nature
4. Intensive sweeteners are prepared by synthetic procedure and provide little or no energy whatsoever; sugar substances eliminate the crucial minerals from your diet
http://www.differencebetween.net/object/difference-between-sugar-and-sweetener/
Answer: The mass of sodium bromide dihydrate is 0.208 grams
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in ml = 250 ml
moles of 
= 
Now put all the given values in the formula of molality, we get
Therefore, the mass of sodium bromide dihydrate is 0.208 grams
Answer:
894 deg K
Explanation:
The computation is shown below:
Given that
V1 denotes the initial volume of gas = 2.00 L
T1 denotes the initial temperature of gas = 25 + 273 = 298 K
V2 denotes the final volume of gas = 6.00 L
T2 = ?
Based on the above information
Here we assume that the pressure is remain constant,
So,
V1 ÷ T1 = V2 ÷ T2
T2 = T1 × V2 ÷ V1
= (298)(6) ÷ (2)
= 894 deg K
Answer:
The first valence electron is removed.
Explanation:
Ionization energy is the energy that is needed to tear out the last electron of an atom in its ground state or gaseous state.
A(g) + IE ----> A+(g) + 1e-
When we talk about starting an electron we refer to the last valence electron, since it is the one that is furthest from the atomic nucleus, the one that does not feel attracted. As the question asks us the opposite, the ionization energy is going to be extremely high, if the electron to be removed occupies the first valence layer, since it is totally attracted to the nucleus.
Answer:
c. 29 J
Explanation:
Step 1: Given data
- Specific heat capacity of Pb (c): 0.13 J/g.K (= 0.13 J/g.°C)
- Initial temperature: 22 °C
Step 2: Calculate the temperature change
ΔT = 37 °C - 22 °C = 15 °C
Step 3: Calculate the heat (Q) required to raise the temperature of the lead piece
We will use the following expression.
Q = c × m × ΔT
Q = 0.13 J/g.°C × 15 g × 15 °C = 29 J
