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Lynna [10]
4 years ago
5

You dissolve 0.37 g of potassium chloride (KCI) in 500 mL of water.

Chemistry
2 answers:
aleksandr82 [10.1K]4 years ago
6 0

Answer: 0.01 M

Explanation:

Molarity is moles of solute/liters of solution.

To find moles, we need to convert 0.37 g of KCl into moles.

30.098g/mol K + 35.45 g/mol Cl = 65.548 g/mol KCl

0.37 g*\frac{mol}{65.548g} =0.00564 mol

Now that we have moles, we need to convert 500 mL to L.

500 mL = 0.5 L

With our moles and liters, we can find molarity.

\frac{0.00564mol}{0.5L} =0.011289M

Significant figures is important. Our answer should be 0.01 M.

pantera1 [17]4 years ago
3 0

Answer:

A. 0.01 M

Explanation:

Molar mass (KCl) = 39.1 + 35.5 = 74.6 g/mol

0.37 g KCl * 1 mol/74.6 g = 0.004960 mol

500 mL = 0.5 L

Molarity = mol solute/L solution = 0.004960 mol/0.5 L = 0.01 M

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4 0
3 years ago
How many liters of O2 gas will be produced at STP from 4 moles of KC1O3
quester [9]

Answer:

V = 134.5 L

Explanation:

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Litters of oxygen produced at STP = ?

Solution:

Chemical equation:

2KClO₃  →  2KCl   + 3O₂

Now we will compare the moles of KClO₃ with oxygen.

                    KClO₃        :           O₂

                        2            :           3

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