4 significant figures (the 0’s are considered significant because they follow a non-zero number)
Explanation:
Plants, as a autotrophs have chlorophyll to capture light energy from sun to make starch and sugar. Then, consumers eat plants, and the sugar is transferred to higher trophic level in a form of organic food. Nevertheless, energy is lost by uneaten food, indigestible food, unabsorbed food, excretory waste (eg co2) and heat loss by respiration.
Answer:
Explanation:
Given,
Mass of block = 75kg
Force of friction=10N
Acceleration of box = 3.60m/s^2
Acceleration due to gravity = 9.8m/s^2
Let tetha represent the angle of inclination.
Wherefore, we have mgsinθ - force of friction = ma........ 1
Substitute the values into equation 1
75×9.8×sinθ -10 = 75×3.60
735sinθ = 10+270
735sinθ = 280
Divide both sides by 735
Sinθ = 280/735
Sinθ = 0.3809
θ = sin^-1 0.3809
θ = 22.389°
We can now solve for the coefficient of friction by considering the formula:
Fs = us×R
Where R = mgcosθ
Fs = 10
10 = Us×75×9.8×cos22.389
10 = Us× 735×0.9246
10 = Us × 679.595
Divide both sides by 679.595
10/679.595 = Us
Us = 0.01471
Hence the coefficient of friction is 0.01471
(a) When you apply a force of 40 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.
(b) When you apply a force of 59 N, the magnitude of the horizontal component of the force that the floor exerts on the block is 51 N.
<h3>Net force on the block</h3>
The horizontal component of the force that the floor exerts on the block is determined by applying Newton's second law of motion;
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
<h3>When the block moves at a constant speed</h3>
![\Sigma F = 0\\\\F - F_f = 0\\\\F = F_f](https://tex.z-dn.net/?f=%5CSigma%20F%20%3D%200%5C%5C%5C%5CF%20-%20F_f%20%3D%200%5C%5C%5C%5CF%20%3D%20F_f)
![F_f = F\\\\F_f = 51 \ N](https://tex.z-dn.net/?f=F_f%20%3D%20F%5C%5C%5C%5CF_f%20%3D%2051%20%5C%20N)
where;
is the frictional force exerted on the block by the floor
Since the surface (floor) is constant, the frictional force (horizontal component of the force that the floor exerts on the block ) will be the same on the cases.
Learn more about frictional force here: brainly.com/question/24386803
Answer:
glucose ,fructose, sucrose,maltose,lactose etc... are some types of sugar.