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Zinaida [17]
2 years ago
11

How much work must be done on a 24-kg shopping cart to increase its speed

Physics
1 answer:
lisov135 [29]2 years ago
8 0

Answer:

The work done by the shopping cart is 180 J  

Explanation:

We have,

Mass of a shopping cart is 24 kg

Initial speed of cart is 1 m/s

Final speed of a cart is 4 m/s

It is required to find the work done by the shopping cart. The work done by an object is also equal to the change in its kinetic energy as per work -energy theorem. It means,

W=\dfrac{1}{2}m(v^2-u^2)

m = 24 kg

u = 1 m/s and v = 4 m/s

W=\dfrac{1}{2}\times 24\times (4^2-1^2)\\\\W=180\ J

So, the work done by the shopping cart is 180 J.

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What do we mean when we say that energy levels are quantized in atoms?
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Answer:

Electrons are located in specific orbit corresponding to discrete energy levels

Explanation:

In Bohr's model of the atom, electron orbit the nucleus in specific levels, each of them corresponding to a specific energy. The electrons cannot be located in the space between two levels: this means that only some values of energy are possible for the electrons, so the energy levels are quantized.

A confirmation of Bohr's model is found in the spectrum of emission of gases. In fact, when an electron jumps from a higher energy level to a lower energy level, it emits a photon whose energy is exactly equal to the difference in energy between the two levels: since the energy levels are discrete, this means that the emitted photons cannot have any value of wavelength, but also their wavelength will appear as a discrete spectrum. This is exactly what it is observed in the spectrum of emission of gases.

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3 years ago
Gravity is greater when there is
Artist 52 [7]
More mass and less difference
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3 years ago
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Water from a river or reservoir enters a hydroelectric power plant through a.....????
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Through a dam... hope this helps:)
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When a cube is inscribed in a sphere of radius r, the length Lof a side of the cube is . If a positive point charge Qis placed a
Nana76 [90]

Answer:

  Ф_cube /Ф_sphere = 3 /π

Explanation:

The electrical flow is

      Ф = E A

where E is the electric field and A is the surface area

Let's shut down the electric field with Gauss's law

       Фi = ∫ E .dA = q_{int} / ε₀

the Gaussian surface is a sphere so its area is

        A = 4 π r²

the charge inside is

        q_{int} = Q

we substitute

       E 4π r² = Q /ε₀

       E = 1 / 4πε₀   Q / r²

To calculate the flow on the two surfaces

* Sphere

       Ф = E A

        Ф = 1 / 4πε₀  Q / r² (4π r²)

        Ф_sphere = Q /ε₀

* Cube

Let's find the side value of the cube inscribed inside the sphere.

In this case the radius of the sphere is half the diagonal of the cube

          r = d / 2

We look for the diagonal with the Pythagorean theorem

         d² = L² + L² = 2 L²

         d = √2 L

         

we substitute

          r = √2 / 2 L

          r = L / √2

          L = √2  r

now we can calculate the area of ​​the cube that has 6 faces

          A = 6 L²

          A = 6 (√2  r)²

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the flow is

          Ф = E A

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          Ф_cubo = 3 /πε₀  Q

the relationship of these two flows is

         Ф_cube /Ф_sphere = 3 /π

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3 years ago
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And that's why commercial radio broadcasting is still analog.
 
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