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3 years ago

How much work must be done on a 24-kg shopping cart to increase its speed

Physics

1 answer:

lisov135 [29]3 years ago

8 0

Answer:

The work done by the shopping cart is 180 J

Explanation:

We have,

Mass of a shopping cart is 24 kg

Initial speed of cart is 1 m/s

Final speed of a cart is 4 m/s

It is required to find the work done by the shopping cart. The work done by an object is also equal to the change in its kinetic energy as per work -energy theorem. It means,

$W=\dfrac{1}{2}m(v^2-u^2)$

m = 24 kg

u = 1 m/s and v = 4 m/s

$W=\dfrac{1}{2}\times 24\times (4^2-1^2)\\\\W=180\ J$

So, the work done by the shopping cart is 180 J.

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3 years ago

A certain 48 V electric forklift can lift up to 7000 lb at a

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Answer:

256.25 A

Explanation:

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2 years ago

A ball that is attached to a string travels in a horizontal, circular path, as shown in Figure 1. At time t0 , the ball has a sp

Levart [38]

Answer:

F₁ = 4 F₀

Explanation:

The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:

F₀ = mv₀²/r --------------- equation (1)

where,

F₀ = Force on string at t₀

m = mass of ball

v₀ = speed of ball at t₀

r = radius of circular path

Now, at time t₁:

v₁ = 2v₀

F₁ = mv₁²/r

F₁ = m(2v₀)²/r

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5 0

3 years ago

Un movil avanza a 20 m/s y recorre una distancia de 800 km. Determinar el tiempo en horas que utiliza

Nataly_w [17]

Answer:

t = 11.1 hours

Explanation:

The question says that, "A mobile advances at 20 m / s and travels a distance of 800 km. Determine the time in hours you use".

Given that,

Speed of a mobile, v = 20 m/s = 72 km/h

Distance, d = 800 km

We know that,

Speed = distance/time

So,

$t=\dfrac{d}{v}\\\\t=\dfrac{800}{72}\\\\t=11.1\ h$

So, it will take 11.1 hours.

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3 years ago

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insens350 [35]

Answer:

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Explanation:

Service equipment and service conductors runs from the service point to the service disconnecting point. Service provides the delivery of electrical energy from it's production point to the consumer where it is meant to be utilized.

3 0

3 years ago