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Zinaida [17]
3 years ago
11

How much work must be done on a 24-kg shopping cart to increase its speed

Physics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

The work done by the shopping cart is 180 J  

Explanation:

We have,

Mass of a shopping cart is 24 kg

Initial speed of cart is 1 m/s

Final speed of a cart is 4 m/s

It is required to find the work done by the shopping cart. The work done by an object is also equal to the change in its kinetic energy as per work -energy theorem. It means,

W=\dfrac{1}{2}m(v^2-u^2)

m = 24 kg

u = 1 m/s and v = 4 m/s

W=\dfrac{1}{2}\times 24\times (4^2-1^2)\\\\W=180\ J

So, the work done by the shopping cart is 180 J.

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A 30 resistor is connected in series with another resistor and a 6. 0V battery. The current in th
Setler79 [48]

Hi there!

We can begin by calculating the voltage drop across the 30 Ω resistor using the equation:

V = IR
V = Potential Difference (V)

I = Current (A)

R = Resistance (Ω)

Calculate the voltage. Recall that the current is CONSTANT across a series circuit.


V = 0.12 × 30 = 3.6 V

Voltage ADDS UP in a series, so:

Total V = V1 + V2

6 = 3.6 + V2

<u>V2 = 2.4V. The correct answer is A.</u>

6 0
2 years ago
An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum
Tju [1.3M]

Answer:

The pressure is  P_2  =  4.25 \ a.t.m

Explanation:

From the question we are told that

   The initial pressure is P_1  =  11.2\ a.t.m

   The  temperature is  T_1 =   299 \ K

   

Let the first volume be  V_1 Then the final volume will be  2 V_1

 Generally for a diatomic  gas

           P_1 V_1 ^r  =  P_2  V_2  ^r

Here r is the radius of the molecules which is  mathematically represented as

    r =  \frac{C_p}{C_v}

Where C_p \  and\   C_v are the molar specific heat of a gas at constant pressure and  the molar specific heat of a gas at constant volume with values

     C_p=7 \  and\   C_v=5

=>   r =  \frac{7}{5}

=>  11.2*( V_1 ^{\frac{7}{5} } ) =  P_2  *  (2 V_1 ^{\frac{7}{5} } )

=>   P_2  =  [\frac{1}{2} ]^{\frac{7}{5} } * 11.2

=>  P_2  =  4.25 \ a.t.m

8 0
3 years ago
What is a device that minimizes the force on a microscopic object during a collision?
liraira [26]
An impact which stops a moving object must do enough work to take away its kinetic energy, so extending the distance moved during the collision reduces the impact force.
3 0
3 years ago
A highway curves to the left with radius of curvature of 36 m and is banked at 26, so that cars can take this curve at higher sp
Katarina [22]

Answer:

Explanation:

Given

radius of track r=36\ m

inclination \theta =26^{\circ}

mass of car m=1477\ kg

coefficient of kinetic friction \mu =0.61

From diagram

N\cos \theta -f_r-mg=0---1

Where N=Normal reaction

f_r=friction

N\cos \theta +f_r\cos \theta =\frac{mv^2}{r}---2

f_r=\mu N----3

From 1 2 and 3 we get  maximum velocity without skidding

v=\sqrt{gr}\times \sqrt{\frac{\tan \theta +\mu}{1-\mu \tan \theta }}

v=\sqrt{9.8\times 36}\times \sqrt{\frac{\tan 26+0.61}{1-0.61\cdot \tan 26}}

v=\sqrt{551.366}

v=23.78\ m/s

4 0
3 years ago
Read 2 more answers
Which notations are commonly used on force diagrams to show forces acting on an object? Check all that apply. Fp Fz FN Ff FD Fg
8090 [49]
Fp, Fn, Ff, Fg. The only reason I know is because I highlighted it in my notes.
8 0
4 years ago
Read 2 more answers
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