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3 years ago

How much work must be done on a 24-kg shopping cart to increase its speed

Physics

1 answer:

lisov135 [29]3 years ago

8 0

Answer:

The work done by the shopping cart is 180 J

Explanation:

We have,

Mass of a shopping cart is 24 kg

Initial speed of cart is 1 m/s

Final speed of a cart is 4 m/s

It is required to find the work done by the shopping cart. The work done by an object is also equal to the change in its kinetic energy as per work -energy theorem. It means,

$W=\dfrac{1}{2}m(v^2-u^2)$

m = 24 kg

u = 1 m/s and v = 4 m/s

$W=\dfrac{1}{2}\times 24\times (4^2-1^2)\\\\W=180\ J$

So, the work done by the shopping cart is 180 J.

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Two identical loudspeakers are some distance apart. A person stands 5.80 m from one speaker and 3.90 m from the other. What is t

NikAS [45]

Answer:

f = 632 Hz

Explanation:

As we know that for destructive interference the path difference from two loud speakers must be equal to the odd multiple of half of the wavelength

here we know that

$\Delta x = (2n + 1)\frac{\lambda}{2}$

given that path difference from two loud speakers is given as

$\Delta x = 5.80 m - 3.90 m$

$\Delta x = 1.90 m$

now we know that it will have fourth lowest frequency at which destructive interference will occurs

so here we have

$\Delta x = 1.90 = \frac{7\lambda}{2}$

$\lambda = \frac{2 \times 1.90}{7}$

$\lambda = 0.54 m$

now for frequency we know that

$f = \frac{v}{\lambda}$

$f = \frac{343}{0.54} = 632 Hz$

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3 years ago

two large boxes sit side by side on a sidewalk. the box on the left has a mass of 80kg and the box on the right has a mass of 50

garri49 [273]

The force that prevents motion when the surfaces of two objects come into contact is known as friction. Friction decreases a machine's mechanical advantage, or, to put it another way, reduces the output to input ratio.

<h3>How can I figure out the frictional force?</h3>

The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value.

The formula fr = Fr/N serves as a representation of it.

Therefore, 100N of force is needed to move an item with a mass of 50 kg.

It will accelerate by 10 m/s2.

If a substance's mass does not change over time, friction cannot affect it. Instead, friction can be affected in a variety of ways by an object's mass.

To Learn more About Friction, Refer:

brainly.com/question/24338873

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1 year ago

What is not changed when work is done by a machine?

Irina18 [472]

B) The amount of work done

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3 years ago

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