Since the two trains are passing in opposite
directions, so this means that their relative velocities will be the sum of the
two trains that is:
<span>
relative velocity = (13 + 28) = 41m/s</span>
<span>
a. The passengers aboard on train B will see that train A is
moving at 41m/sec due east</span>
<span>b. The passengers aboard on train A will see that
train B is moving at 41m/sec due west</span>
Answer:
103.4° or S76.6°E
Explanation:
The direction N43°E is perpendicular to the direction south-east when the plane turn 90° and heads in the south-east direction.
Since the distance 1/2 mile N43°E is perpendicular to the distance 1 mile south-east, we have a right angled triangle.
So, the angle θ between the aircraft's new position and old position is gotten from tanθ = 1 ÷ 1/2 = 2
θ = tan⁻¹(2) = 63.43°
So, the total angle from North to its new position is 40° + 63.43° = 103.43°
Since we need the south-east bearing, the angle from south is 180° - 103.43° = 76.57° ≅ 76.6°
So, our bearing is 103.4° or S76.6°E
The distance between city a and city b is 833.345 miles.
We know that
1°=60'
The distance of city a from the initial ray is calculated as
x_a=3960*tan45.46°=4024.101 miles
The distance of city b from the initial ray is calculated as
x_b=3960*tan 38.86°=3190.75 miles
Now the distance between city a and b is equal to
4024.101-3190.75=833.345 miles
This is the vertical distance between the cities.
Answer:
Convergent boundaries: where two plates are colliding.
Divergent boundaries – where two plates are moving apart.
Transform boundaries – where plates slide passed each other.
