Answer:
<em>The second person will have a velocity of 0.85 m/s in the opposite direction of the first person.</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum</u>
The total momentum of a system of bodies is conserved unless an external force is applied. The formula for the momentum of a body with mass m and velocity v is:
P=mv.
If we have a system of bodies, then the total momentum is the sum of them all
If a collision occurs, the velocities change to v' and the final momentum is:
In a system of two masses, the law of conservation of linear momentum is:
According to the conditions of the problem, two persons standing on a frictionless surface are initially at rest (v1=0, v2=0). Their masses are m1=50 Kg and m2=65 Kg. After the push, one person (say m1) moves backward at v1'=-1.1 m/s. We can calculate the speed of the other person by solving for v2':
Substituting:
The second person will have a velocity of 0.85 m/s in the opposite direction of the first person.
Answer:
El esfuerzo cortante, de corte, de cizalla o de cortadura es el esfuerzo interno o resultante de las tensiones paralelas a la sección transversal de un prisma mecánico como por ejemplo una viga o un pilar. Se designa variadamente como T, V o Q.
Este tipo de solicitación formado por tensiones paralelas está directamente asociado a la tensión cortante. Para una pieza prismática se relaciona con la tensión cortante mediante la relación:
(1){\displaystyle Q_{y}=\int _{\Sigma }\tau _{xy}\ dydz,\qquad Q_{z}=\int _{\Sigma }\tau _{xz}\ dydz,\qquad Q={\sqrt {Q_{y}^{2}+Q_{z}^{2}}}}
Para una viga recta para la que sea válida la teoría de Euler-Bernoulli se tiene la siguiente relación entre las componentes del esfuerzo cortante y el momento flector:
Work done = force × distance travelled in the direction of the force
Force= 2(9.81) = 19.62N
WD= 19.62×130= 2550.6Nm
Answer:
torque on the loop is 0.9812 Nm
Explanation:
given,
circular loop of 200 turns
radius = 65 cm
current in the loop = 85 A
Earth field is pointed north, but at an angle 45.0°
B = 6.15 × 10⁻⁵ T
torque on the loop = ?
using formula
hence, torque on the loop is 0.9812 Nm
Not 100% but i think it'll cause the earth to rotate slightly slower, its definitely not the last one though