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xxTIMURxx [149]
3 years ago
15

On a map the distance from Fort Collins to Cheyenne is 3.2 inches. The angle formed at Laramie has measure 43.6º, and the angle

formed at Fort Collins has measure 46.5º. If one inch on the map is equal to 10.6 miles, find the distance from Cheyenne to Laramie to the nearest whole mile
Mathematics
1 answer:
MArishka [77]3 years ago
7 0
We can solve this by drawing a triangle with three points. The first point at Fort Collins (F), the second at Cheyenne (C) and the third at Laramie (L).

The angle at F = 46.5, the angle at L = 43.6. We know the side opposite angle L = 3.2 (side FC), now we must solve for the side opposite angle F (side LC).

We can use the law of sines to solve this where:

sinA/a = sinB/b
sin43.6/ 3.2 = sin46.5/LC
LC = 3.2 (sin46.5/sin43.6)
LC = 3.37 inches

We are told 1 in = 10.6 miles, therefore:

3.37 inches x 10.6 miles/in = 36 miles from Laramie to Cheyenne.
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B>a 

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<span>3a-22+2a=98 </span>

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<span>So the smaller number is 24 and the larger number is 50.</span>
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3 years ago
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A basketball player makes 75% of her free throws. If she made 84 free throws this season, how many has she attempted?
myrzilka [38]
If you would like to know how many free throws did a basketball player attempted, you can calculate this using the following steps:

75% of x is 84
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x = 84 * 100 / 75
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The correct result would be 1<span>12 free throws.</span>
8 0
3 years ago
Order each set of numbers from least to greatest {7 , 9 √50, √85
Oksi-84 [34.3K]

Answer:

7,√50,9,√85

Step-by-step explanation:

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3 years ago
The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

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Now area of the wall = 69 + 180 + 121

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One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

                                                       = £105

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