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mars1129 [50]
3 years ago
15

What is 10 * 10 *100 because it is hard?

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0
10x10x100=
10000 
Would be the answer hope this helped.

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56 divided by 8"s goinhbllllllll
dmitriy555 [2]
The answer is 7 hope this helped
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4 years ago
Make a list of all the different sums that can appear on two six sided dice?
kenny6666 [7]

answer: Rolling Two Dice. Note that there are 36 possibilities for (a,b). This total number of possibilities can be obtained from the multiplication principle: there are 6 possibilities for a, and for each outcome for a, there are 6 possibilities for b. So, the total number of joint outcomes (a,b) is 6 times 6 which is 36.

Step-by-step explanation: hopefully this is right

7 0
3 years ago
A quadratic function and an exponential function are graphed below. How do the decay rates of the functions compareover the inte
Kobotan [32]

To check the decay rate, we need to check the variation in y-axis.

Since our interval is

-2We need to evaluate both function at those limits.At x = -2, we have a value of 4 for both of them, at x = 0 we have 1 for the exponential function and 0 to the quadratic function. Let's call the exponential f(x), and the quadratic g(x).[tex]\begin{gathered} f(-2)=g(-2)=4 \\ f(0)=1 \\ g(0)=0 \end{gathered}

To compare the decay rates we need to check the variation on the y-axis of both functions.

\begin{gathered} \Delta y_1=f(-2)-f(0)=4-1=3 \\ \Delta y_2=g(-2)-g(0)=4-0=4 \end{gathered}

Now, we calculate their ratio to find how they compare:

\frac{\Delta y_1}{\Delta y_2}=\frac{3}{4}

This tell us that the exponential function decays at three-fourths the rate of the quadratic function.

And this is the fourth option.

4 0
1 year ago
Solve the equation.<br> у<br> _= 16<br> 8
KATRIN_1 [288]
Hahahhaha ushsbhakansbuskwmjapa
4 0
3 years ago
If the quantity 4 times x squared times y squared plus 8 times x cubed times y to the fifth power all over 2 times x times y squ
motikmotik

Answer:

c=2

Step-by-step explanation:

(4x^2 y^2 + 8x^3 y^5) / (2x y^2) = 4x^2 y^2 / 2x y^2 + 8x^3 y^5 / 2x y^2 = 2x + 4x^2 y^3

Therefore, a = 1, b = 0, c = 2 and d = 3

4 0
3 years ago
Read 2 more answers
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