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Hitman42 [59]
3 years ago
13

After teaching a group of nursing students about diuretics, the instructor determines that the teaching was successful when the

group identifies which as a loop diuretic?
Biology
1 answer:
ANTONII [103]3 years ago
6 0

Answer:

Nursing students will understand the diuretics of Asa are those, which will exert their effect at the level of the ascending portion of the loop of Henle, where they will produce inhibition of chlorine and sodium reabsorption. These diuretics increase their inhibitory action if we increase their dose. In medicine this type of medication is used in patients who present with edema caused by congestive heart failure or kidney failure.

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You are working as a botanist in a tropical forest and have located a small plant that has never before been seen or classified.
vichka [17]

Answer: Pteridophyte

You classify the plant as a pteridophyte

Explanation:

Pteridophytes are known to have the following:

- many cells (multicellular) and vascular bundles

- true roots, stems, and leaves

- do not produce flower throughout their lifespan

- they are mainly terrestrial plants, while few are aquatic

- do not produce seeds but reproduce asexually by formation of spores

Examples are ferns

8 0
3 years ago
Explain how the 3’ and the 5’ end of the DNA molecule affects DNA replication.
Fed [463]

Answer:

The DNA is read in the 3' to 5' direction but copied in the 5' to 3' direction

The new strand will be like the  reverse of the template strand

5 0
3 years ago
Imagine you are a geneticist interested in studying a newly discovered species of very colorful birds. You have found that a sin
kolbaska11 [484]

The frequency <em>p</em> of the yellow (A) allele is  <em>p</em>= 0.3

The frequency <em>q</em> of the blue (a) allele is  <em>q= </em><em>0.7</em>

Hardy–Weinberg equilibrium,  states that allele and genotype frequencies in a population will remain constant from generation to generation. Equilibrium is reached in the absence of selection, mutation, genetic drift and other forces and allele frequencies p and q are constant between generations. In the simplest case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes.  

p²+2*p*q+q²= 1       p+q= 1     q= 1-p

yellow (p²)= 9%= 0.09               p= √0.09= 0.3

green (2*p*q)= 42%= 0.42        

blue (q²)=49%= 0.49                q=1-0.3= 0.7 <em>or</em> q= √0.49= 0.7


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What part of contingency planning process came up short (ir, bp, or cp)?
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