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JulijaS [17]
3 years ago
8

According to the reading, all of the following are true about enzymes except:

Biology
1 answer:
dem82 [27]3 years ago
7 0

Enzymes are biological molecules which serve as catalysts for various reactions in the body.

Enzymes are known to catalyze various biochemical processes in the body and are indispensable in the body. The untrue statement about enzymes is that all enzymes have the same shape. Since enzymes are specific and they work in a lock and key model. Each enzyme has a unique shape that suits its substrate.

Each enzyme binds to an active site. The active site refers to the part of the body where the enzyme discharges its function as shown in the figure.

Since an enzyme does not participate in a chemical reaction, the enzyme will remain unchanged at the end of the reaction. Enzymes are proteins, this is the group of biological molecules to which they belong.

Learn more: brainly.com/question/1124096

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natita [175]

The image shows a red blood cell in different solution. The first image shows an RBC in a hypotonic solutions. The RBC swell and lyse because of the osmotic movement or referred to as hemolysis. The second image shows a normal RBC in an isotonic solution. There is no net change of water to the RBC. The third image shows a shriveled RBC in a hypertonic solution. The water leak out of the RBC briskly than it enters the cell. It is also called as crenated cell.

Answer - Option C - hypotonic solution

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1 year ago
Solar tracking, or _____, is a plant's growth toward light.
GrogVix [38]
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eg: photosynthesis
5 0
3 years ago
In beans the pod texture and growth form genes are located on different chromosomes. There are two varieties of beans in a farme
irina1246 [14]

Answer:

a. Genotype in F1 - TtBb

   Phenotype in F1 - tough pods, bush-type growth

b. Proportion of F2 that are heterozygous for bush-type growth form = 5/8

c. Proportion of the F2 with tender pods =  1/4

d. Proportion of F2 that are heterozygous for growth form and have tender     pods = 1/8

Explanation:

Since the two traits are located on different chromosomes, they will independently assort during gametes formation. T is dominant over t and B is dominant over b.

Two true-breeding varieties were crossed at the beginning of the program:

TTBB   x   ttbb

All F1 plants will have the genotype TtBb with tough pods and bush-type growth form.

Advancing the cross to F2:

TtBb   x   TtBb

Progeny

1 TTBB   -   tough pods, bush-type

2 TTBb     -  tough pods, bush-type

2 TtBB    -   tough pods, bush-type

4 TtBb     -   tough pods, bush-type

1 TTbb     -    tough pods, climbing-type

2 Ttbb     -    tough pods, climbing-type

1 ttBB       -    tender pods, bush-type

2 ttBb     -      tender pods, bush-type

1 ttbb      -      tender pods, climbing-type

<em>Proportion of F2 that are heterozygous for bush-type growth form = 10/16 = 5/8</em>

<em>Proportion of the F2 with tender pods = 4/16 = 1/4</em>

<em>Proportion of F2 that are heterozygous for growth form and have tender pods = 2/16 = 1/8</em>

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