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Zigmanuir [339]
3 years ago
8

John took 3 exams so far this semester. He scored 45, 65 and 80 on those 3 exams . What score does he need on the fourth exam to

average 70 or more on his exams?
Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

He \: needs \: to \: score \: 90 \: or \: more

Step-by-step explanation:

\frac{x + 45 + 65 + 80}{4}  \geqslant 70\Leftrightarrow x + 190 \geqslant 280\Leftrightarrow x \geqslant 90

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Question 1:
Morgarella [4.7K]

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Step-by-step explanation:

KE = ½mv²

KE₁₀ = ½(1100)10² = 55000 = 55 kJ

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9 times greater

3 0
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Alika [10]
Can you please post the image.
7 0
4 years ago
Simplify the expressions by combining like terms<br><br> 4r + 9r - 11r + 7r
konstantin123 [22]
9r
Explanation:
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4 0
3 years ago
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Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
Find y when x = 12, if y = 2 when x = 5
AleksAgata [21]
Y = kx
k = y/x
k = 2/12
k = 1/6

so when x = 12
y = kx
y = 1/6(5)
y = 5/6

answer
when x = 5  y = 5/6
7 0
3 years ago
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